Balanced Half reactions are:
At anode 2
==> Cl₂+
+ H₂O ==>
+ 2
+
At Cathode: 2
+
==> H₂
Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O,
,
and 
Now at Anode reaction will occur as given:
2
==> Cl₂+
+ H₂O ==>
+ 2
+
(will occur)
At Cathode:
2
+
==> H₂ (will occur)
At Cathode:
+
==> Mn (This reaction will not occur)
The deposition of solid Mn will not occur because in aqueous solution,
will be reduced before
.
The reduction potentials for
is zero whereas reduction potential for
is - 1.18V.
The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.
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The best description of Ernest Rutherford's experiment is letter C. The positively charged particles were fired through a gold foil. Most of these particles went right through, while others bounced back. This experiment led to the discovery of the nucleus.
The enol carbon or ∝-carbon nucleophile attacks at molecular bromine in the acid-catalyzed α-bromination of a ketone
Treatment of ketones with bromine in the presence of acid will results in formation of a new C-Br bond at the alpha position. The purpose of the acid is to catalysed formation of the enol from ketone , which is active nucleophile in the reaction. This reaction is called haloform reaction which is used to identify the methyl substituted ketone in the presence of aldehyde.
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