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lbvjy [14]
3 years ago
10

based on the techniqes yo have learned in the organic chemistry lab how would you seperate any unreated alcohol from the ester

Chemistry
1 answer:
mihalych1998 [28]3 years ago
3 0

Answer:

Fractional distillation and HP-LC

Explanation:

This is a technique useful for analytes with close boiling points. Any alcohol-ester azotopes can be further refined using high-performance liquid chromatography (HP-LC) column.

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Answer:

1) Favor formation of reactant

2) Favor formation of product

3) Favor formation of product

4) Favor formation of product

5) Favor formation of product

Explanation:

The reaction is AgBr(s)--->Ag^{+}(aq)+Br^{-}(aq)

The reaction is endothermic

1. Adding hydrobromic acid (HBr)

It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.

2. Lowering the concentration of bromide (Br-) ions

As we are decreasing the the concentration of product it will favor formation of more products

3. Heating the concentrations

If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.

4. Adding solid silver bromide (AgBr)

If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products

5. Removing silver (Ag+) ions

Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.

3 0
3 years ago
cytoplasm streams within a cell, moving materials somewhat as ocean currents move a raft . in which cell will materials move fas
Scorpion4ik [409]
Because cytoplasm is made of a jelly like consistent
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3 years ago
In the operation of the Heat Transfer Service Unit, one of the variables you can control is the rate of cooling water flowing ag
max2010maxim [7]

Answer:

A. The rate of heat transfer through the material would increase.

Explanation:

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So if we increase the rate of flow of cooling water and the other variables that ypu can control remain the same, the result is that the rate of heat transfer through the material would increase, as it is stated in option a.

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