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lisov135 [29]
4 years ago
10

A large ant is standing on the middle of a circus tightrope that is stretched with tension T_s. The rope has mass per unit lengt

h mu. Wanting to shake the ant off the rope, a tightrope walker moves her foot up and down near the end of the tightrope, generating a sinusoidal transverse wave of wavelength lambda and amplitude A. Assume that the magnitude of the acceleration due to gravity is g.
What is the minimum wave amplitude A_min such that the ant will become momentarily weightless at some point as the wave passes underneath it? Assume that the mass of the ant is too small to have any effect on the wave propagation.
Physics
1 answer:
k0ka [10]4 years ago
3 0

Answer:

A = \frac{g \lambda^2 \mu}{4\pi^2 T_s}

Explanation:

As we know that the speed of the wave in string is given as

v = \sqrt{\frac{T_s}{\mu}}

now we will have

frequency of the wave is given as

f = \frac{v}{\lambda}

f = \frac{1}{\lambda}\sqrt{\frac{T_s}{\mu}}

now if the ant will feel weightlessness then we will have

mg = m\omega^2 A

so we will have

A = \frac{g}{\omega^2}

A = \frac{g}{4\pi^2 f^2}

A = \frac{g \lambda^2 \mu}{4\pi^2 T_s}

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A 94 g particle undergoes SHM with an amplitude of 8.3 mm, a maximum acceleration of magnitude 7.8 x 103 m/s2, and an unknown ph
Lelechka [254]

Answer:

a) T = 6.49*10^-3 s

b) v = 8 m/s

c) E = 3 J

d) F = 733 N

e) F = 366.5 J

Explanation:

Given

Mass of particle, m = 94 g = 0.094 kg

Amplitude of the particle, A = 8.3 mm = 8.3*10^-3 m

Maximum acceleration of particle, a = 7.8*10^3 m/s²

the equation describing Simple Harmonic Motion is given as

x = A cos (wt +φ)

To fond the acceleration of this relationship, we would have to integrate. Twice, the first would be a Velocity, and the second acceleration that we need.

Velocity = dx/dt = -Aw sin(wt + φ)

Acceleration = d²x/dt = -Aw² cos(wt + φ)

From the question, we were given, magnitude of acceleration to be 7.8*10^3 m/s²

Aw² = 7.8*10^3

w² = 7.8*10^3 / A

w² = 7.8*10^3 / 8.3*10^-3

w² = 939759

w = √939759

w = 969

Recall, T = 2π/w, so that

T = (2 * 3.142) / 969

T = 6.49*10^-3 s

Maximum speed = Aw

Maximum speed = 8.3*10^-3 * 969

Maximum speed = 8.0 m/s

Total mechanical energy oscillator =

mgx + 1/2mx² =

1/2mv(max)² =

1/2 * 0.094 * 8² =

3 J

Maximum displacement

x = A cos(wt + φ)

For x to be maximum here, then cos(wt + φ) Must be equal to 1

Acceleration = d²x/dt² = -Aw²

And force = mass * acceleration

Force = 0.094 * 7.8*10^3

Force = 733 N

x = A cos(wt + φ), where cos(wt + φ) = 1/2

d²x/dt² = -Aw² * 1/2

d²x/dt² = 733 * 0.5

= 366.5 N

7 0
3 years ago
A coin is located 35.0 mm from the center of a turntable which accelerates from rest to a speed of 7.95 rad/s in 0.270 s. What i
beks73 [17]

The minimum coefficient of friction to avoid slippage of the coin is 0.23.

<h3>Minimum coefficient of friction</h3>

The minimum coefficient of friction can determined from the maximum speed of the coin.

ma = μmg

mv²/r = μmg

v²/r = μg

v² = μgr

μ = v²/(gr)

μ = (ωr)²/(gr)

μ = ω²r/g

μ = (7.95² x 0.035)/(9.8)

μ = 0.23

Learn more about coefficient of friction here: brainly.com/question/20241845

#SPJ11

5 0
2 years ago
A car with a mass of 1,600 kg is traveling at a speed of 25 m/s. What is the momentum of
tamaranim1 [39]
40,000 kg m/s
Momentum = mass * velocity
= 1600 * 25
= 40,000
3 0
3 years ago
A musician hits a drum with a drumstick. In three to four sentences, explain the collision forces between the drum and drumstick
Gnoma [55]

Answer:

Explanation:

In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. When you hit a drum with a drumstick, there is a collision. The force both objects release causes the drumstick to bounce on the drum

4 0
3 years ago
If a car travels 80 miles between 2 and 4 pm, then its velocity is close to 40 mph at 2 pm.
Alisiya [41]
The answer should be false because it doesnt say if the car is traveling at constant speed. The cars speed can be various so that in total for 2 hours that it travels it passes 80 miles. If however it actually traveled at constant speed than the answer is true.
3 0
4 years ago
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