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trapecia [35]
2 years ago
6

Question 4 What would be the UCS for Tab the dog? O The shock O The flowers and fence O Fear O The boundary Question 5​

Physics
1 answer:
Harrizon [31]2 years ago
3 0

The unconditioned stimulus (UCS) for Tab the dog is: B. The flowers and fence.

<h3>The types of stimuli.</h3>

In Science, the two (2) stimuli that are repeatedly paired in classical conditioning include:

  • Conditioned stimulus
  • Unconditioned stimulus

<h3>What is an unconditioned stimulus?</h3>

An unconditioned stimulus can be defined as a stimulus that is capable of naturally triggering a response, before or without any conditioning while it elicit a specific response without learning.

  • This ultimately implies that, an unconditioned stimulus leads to an automatic response in a living organism such as a dog.

In this scenario, the unconditioned stimulus (UCS) for Tab the dog is simply the flowers and fence.

Read more on unconditioned stimulus here: brainly.com/question/24868138

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A soccer ball with mass 0.450 kg is initially moving with speed 2.20 m/s. A soccer player kicks the ball, exerting a constant fo
Alinara [238K]

Answer:

0.187 m

Explanation:

We'll begin by calculating the acceleration of the ball. This can be obtained as follow:

Mass (m) = 0.450 Kg

Force (F) = 38 N

Acceleration (a) =?

F = m × a

38 = 0.450 × a

Divide both side by 0.450

a = 38 / 0.450

a = 84.44 m/s²

Finally, we shall determine the distance. This can be obtained as follow:

Initial velocity (u) = 2.20 m/s.

Final velocity (v) = 6 m/s

Acceleration (a) = 84.44 m/s²

Distance (s) =?

v² = u² + 2as

6² = 2.2² + (2 × 84.44 × s)

36 = 4.4 + 168.88s

Collect like terms

36 – 4.84 = 168.88s

31.52 = 168.88s

Divide both side by 168.88

s = 31.52 / 168.88

s = 0.187 m

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6 0
3 years ago
A particle of mass m moves under an attractive central force F(r) = -Kr4 with angular momentum L. For what energy will the motio
docker41 [41]

Answer:

Angular velocity is same as frequency of oscillation in this case.

ω = \sqrt{\frac{7K}{m} } x [\frac{L^{2}}{mK}]^{3/14}

Explanation:

- write the equation F(r) = -Kr^{4} with angular momentum <em>L</em>

- Get the necessary centripetal acceleration with radius r₀ and make r₀ the subject.

- Write the energy of the orbit in relative to r = 0, and solve for "E".

- Find the second derivative of effective potential to calculate the frequency of small radial oscillations. This is the effective spring constant.

- Solve for effective potential

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3 0
3 years ago
A small apple weighs 0.8N. How much would an apple that is 4 times as massive weigh?
-BARSIC- [3]

Answer:

W=31.99 N

Explanation:

W= 8 N (N= kg*m/ s^2)

W= m* g

8 N= m * 9.8 m/s^2

m= 0.816 kg

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= 3.264 kg

W= mg

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W=31.99 N

4 0
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