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3 years ago

A track coach records how long it takes a sprinter to run 100 meters the track coach is recording what dimension of behavior

1 answer:

5 0

Behavior has at least six dimensions, which are: frequency, duration, latency, topography, locus, and force. Since the coach is recording how long it takes, the track coach is recording the duration behavior because duration is a synonym for time. Duration is your answer.

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Add the following displacement vectors: <br> 12 m south and 15 m 55° E of N??

daser333 [38]

12m S=0m E, -12m N
15m 55d E of N = 15 sin 55, 15 cos 55 N
Sum= (15sin55)m E, (-12 + 15 cos 55)m N

4 0

3 years ago

Suppose your car is on a 5% grade, meaning that for every 100 m you travel along the road you raise or lower only 5 m in elevati

kvv77 [185]

Answer:

734.215N

Explanation:

First we calculate the angle that corresponds to a 5% slope using the Tan-1 function

$\beta = tan-1(5%)=2.86$

then we use the component that corresponds to the direction parallel to the road, additionally we must multiply by the gravity value to find the weight(g=9.81m/s^2)

Wx=M*g*sen(2.86)=1500kg*9.81*sen(2.86)=734.215N

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3 years ago

Read 2 more answers

How do valence electrons relate to the chemical reactions of an element?

11111nata11111 [884]

Valence electrons are required for certain bonding processes. Without them you cannot bond with certain elements. For example, carbon bonds really well with carbon because it has the same amount of valence electrons. However carbon would not bond well with uranium due to the massive differences in valence electrons. Hope this helps!

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3 years ago

An object is accelerating from rest at a rate of 3 m/s2.How long will it take the object to attain 18 m/s ? *

Temka [501]

Initial velocity =0, a=3m/s2, final velocity =18m/s, 18=3t, t=6 sec

7 0

3 years ago

With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what

kenny6666 [7]

The magnitude of the displacement current between the plates is $2.1*10^{-8} A$

Given,

A=4.3* $10^{-2} m^{2}$

$E=(4.0*10^{5})-(6.0*10^{4}t)\\$

$i_{d} =ϵ_{0} *\frac{dϕ_{E} }{dt } =ϵ_{0}A\frac{dE}{dt}$

$i_{d}$ = $ϵ_{0}$ *A* $\frac{d}{dt}$ $(4.0*10^{5})-(6.0*10^{4}t)$ = $-ϵ_{0} *A*6.0*10^{4}$

= - $(8.85*10^{-12})(4.0×10*^{-2})(6.0×10^{4})$ = $-2.1*10^{-8} A$

<h3>Current </h3>

An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. The capital letter I is frequently used as a symbol for current. Amperes are the common unit and are denoted by the letter A. A coulomb of electrical charge moves past a certain place in one second as one ampere of current does. Franklin current or conventional current are terms used by physicists to describe how current flows from relatively positive to comparatively negative sites. Negatively charged electrons are the most prevalent charge carriers. They move in a somewhat good direction from relatively negative points.

With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what is the magnitude of the displacement current between the plates?

Learn more about current here:

brainly.com/question/13076734

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5 0

1 year ago