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ale4655 [162]
3 years ago
11

Butane gas is used as the fuel in disposable lighters. It burn in oxygen to form carbon dioxide gas and water vapor. What mass o

f carbon dioxide is produced when 53.3 g of butane is burned in 103.9 g of oxygen
Chemistry
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

mass of carbon dioxide produced = 87.9153846154 g   ≈  87.92 g

Explanation:

The chemical equation is as follow

Butane = C4H10

oxygen = O2

carbon dioxide = CO2

water = H2O

C4H10 + O2 →  CO2 +  H2O

The equation should be balanced before solving it.

2C4H10 + 13O2 →  8CO2 +  10H2O

molar mass of 13 mole of oxygen = 416 g

molar mass of 8 mole of carbon dioxide = 256 + 96 = 352 g

416 g of oxygen was needed to produce 352 g of carbon dioxide

103.9 g will produce  ?

cross multiply

mass of carbon dioxide produced = 103.9 × 352/416

mass of carbon dioxide produced = 103.9 × 352/416

mass of carbon dioxide produced = 36572.8 /416

mass of carbon dioxide produced = 87.9153846154 g ≈  87.92 g

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