Answer:
TRUE
Explanation:
remember newtons laws of motion. Every action has an equal and opposite reaction. LOL
C2H4 is oxidized and O2 is reduced in both reactions.
<h3>What is oxidation/reduction?</h3>
Oxidation is defined in several ways. Some of the definitions are:
- The addition of oxygen or removal of hydrogen
- Increase in the oxidation number of atoms
- Addition of electronegative or the removal of electropositive elements
Reduction, on the other hand, is defined as:
- Removal of oxygen or addition of hydrogen
- Decrease in the oxidation number of atoms
- Addition of electropositive elements or the removal of electronegative elements.
In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.
The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.
More on oxidation and reduction can be found here: brainly.com/question/3867774
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Answer
is: volume is 20 mL.<span>
c</span>₁(CH₃COOH) = 2,5 M.<span>
c</span>₂(CH₃COOH) = 0,5 M.<span>
V</span>₂(CH₃COOH) = 100 mL.<span>
V</span>₁(CH₃COOH) = ?<span>
c</span>₁(CH₃COOH) · V₁(CH₃COOH)
= c₂(CH₃COOH) · V₂(CH₃COOH).<span>
2,5 M · V</span>₁(CH₃COOH)
= 0,5 M · 100 mL.<span>
V</span>₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.<span>
V</span>₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.
