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Oksi-84 [34.3K]
4 years ago
7

How many colors are present in light

Physics
2 answers:
Step2247 [10]4 years ago
7 0
There are 7 colors which are red, orange, yellow, green, blue, indigo and violet
Delvig [45]4 years ago
3 0
Hello there.

Question: <span>How many colors are present in light

Answer: It would be 7. They are red, orange, yellow, green, blue, indigo and violet. That is the visible spectrum.

Hope This Helps You!
Good Luck Studying ^-^</span>
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The most narrow region of the electromagnetic spectrum is
Lostsunrise [7]

The answer is A. X rays or it can be visible light but mostly A.


4 0
3 years ago
A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and
balandron [24]

The upward force exerted on the board by the support is mathematically given as

Fu= 764.8 N

<h3>What is the upward force exerted on the board by the support?</h3>

Generally, the equation for is  mathematically given as

Considering that the Net Force on the system is null

The weight of the children plus the weight of the board equals the upward force imposed on the support.

The upward force

Fu= 440 + 272 + 52.8 N

Fu= 764.8 N

In conclusion, he upward force exerted on the board by the support

Fu= 764.8 N

Read more about force

brainly.com/question/13191643

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8 0
2 years ago
CORRECT ANSWER WILL BE REWARDED BRAINLIEST
Mandarinka [93]

Answer:

What is 2^-3 x 3^-2 as a fraction?

What is (-2)^-3 x (-3)^-2 as a fraction

Explanation:

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7 0
3 years ago
What caused the light to shine on the paper above the mirror?
Shalnov [3]

Answer:

The Light was reflected, b.

Explanation:

If the flashlight was pointed at the mirror, it was reflected because it did not stop on the mirror or go through the mirror or reflect in different ways.

4 0
3 years ago
You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of
Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}

\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}

Solve s'

\frac{1}{s'}  = \frac{2}{1.50 m} - \frac{1}{2.0 m}

\frac{1}{s'} =  1.833 m

s' = - 0.545 m

To determine the speed of the trick to the highway

\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}

\frac{ds}{dt} = 26.88 m/s

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0
3 years ago
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