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3 years ago

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The theoretical yield of ammonia in an industrial synthesis was 550 kg, but only 480 kg was obtained. What was the percentage yi

eld of the reaction?

1 answer:

bezimeni [28]3 years ago

8 0

Theoretical yield 550 kg - 100%

Actual yield 480 kg - x%

x= 480*100/550 ≈ 87.3 %

Percentage yield ≈ 87.3 %.

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The chemical formula for lithium fluoride is lif . a chemist determined by measurements that 0.035 moles of lithium fluoride par

Mnenie [13.5K]

Answer:
mass = 0.907865 grams

Explanation:
From the periodic table:
molar mass of Li = 6.941 grams
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3 years ago

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3 years ago

Suppose a 1.0 L solution contains 0.020 M in Cu(NO3)2, then 0.40 moles of NH3 are added. Assuming no change in volume, what is t

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Answer:

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$Cu^{2+}+4NH_3_{aq} \rightleftharpoons [Cu(NH_3)_4]^{2+}_{(aq)}$

Initial (M) 0.020 0.40 0

Change (M) - x - 4 x x

Equilibrium (M) 0.020 -x 0.40 - 4 x x

Given that: $K_f =1.7*10^{13}$

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Since x is so small; 0.40 -4x = 0.40

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$1.7*10^{13} = \frac{x}{(5.12*10^{-4}-0.0256x)}$

$1.7*10^{13}(5.12*10^{-4} - 0.0256x) = x$

$8.704*10^9-4.352*10^{11}x =x$

$8.704*10^9 = 4.352*10^{11}x$

$x = \frac{8.704*10^9}{4.352*10^{11}}$

$x = 0.0199999999999540$

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$Cu^{2+} = 4.6*10^{-14}$ M

8 0

3 years ago