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3 years ago

8

Sensors detect the concentration of mercaptan molecules in natural gas at various distances from a leaking source . At which loc

ation will a sensor detect the highest concentration of mercaptan ?

1 answer:

chubhunter [2.5K]3 years ago

4 0

One meter in front of the source at this location will a sensor detect the highest concentration of mercaptan.

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3. At STP, how many liters of oxygen gas are required to react completely with 3.2 x 10^22

Mrrafil [7]

The volume of oxygen required to react with 3.2 * 10²² molecules of hydrogen is 0.56 L.

<h3>What is stoichiometric law?</h3>

The stoichiometric law has been given as the representation of the moles of product and reactant in a chemical reaction are represented by the stoichiometric coefficient.

It has been known that 1 mole of a compound has 6.023 * 10²³ molecules. Thus, the moles of hydrogen gas equivalent to 3.2 * 10²² molecules has been:

6.023 * 10²³ molecules = 1 mole

3.2 * 10²² molecules = 1/6.023 * 10²³ * 3.2 * 10²² moles

3.2 * 10²² molecules = 0.05 moles

Thus, the moles of hydrogen gas available is 0.05 moles.

From the stoichiometric law, according to the balanced chemical equation,

2 moles of hydrogen requires = 1 moles of oxygen

0.05 moles of hydrogen requires = 1/2 * 0.05 moles oxygen

0.05 moles of hydrogen requires = 0.025 moles oxygen

Thus, the moles of oxygen required is 0.025 moles. At STP, a mole of gas been equivalent to 22.4 L . Thus, the volume of 0.025 moles oxygen has been:

1 mole = 22.4 L

0.025 moles = 22.4 * 0.025 L

0.025 mole = 0.56 L

Thus, the volume of oxygen required to react with 3.2 * 10²² molecules of hydrogen is 0.56 L.

Learn more about stoichiometric law, here:

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2 years ago

WHAT IS NORMAL MUSCLE PH

larisa [96]

The skeletal muscle ph is typically 7.15

8 0

3 years ago

What is the number of Valence Electrons for Chlorine?

Alex_Xolod [135]

Answer:

7

Explanation:

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3 years ago

A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

natali 33 [55]

Answer:

There are 0.93 g of glucose in 100 mL of the final solution

Explanation:

In the first solution, the concentration of glucose (in g/L) is:

15.5 g / 0.100 L = 155 g/L

Then a 30.0 mL sample of this solution was taken and diluted to 0.500 L.

30.0 mL equals 0.030 L (Because 30.0 mL ÷ 1000 = 0.030 L)

The concentration of the second solution is:

$155 \frac{g}{L} *\frac{0.030L}{0.500L}=9.3\frac{g}{L}$

So in 1 L of the second solution there are 9.3 g of glucose, in 100 mL (or 0.1 L) there would be:

1 L --------- 9.3 g

0.1 L--------- Xg

Xg = 9.3 g * 0.1 L / 1 L = 0.93 g

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3 years ago

Use sedimentary in a sentence

VMariaS [17]

'The Sedimentary rock formed from years of sediments piling on top of it and being compressed.'

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2 years ago

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