Answer: 473.640 m
Explanation:
This situation is related to projectile motion or parabolic motion, in which the travel of the cannonball has two components: x-component and y-component. Being their main equations as follows:
x-component:
(1)
Where:
is the cannonball's initial velocity
because we are told the cannonball is shot horizontally
is the time since the cannonball is shot until it hits the ground
y-component:
(2)
Where:
is the initial height of the cannonball
is the final height of the cannonball (when it finally hits the ground)
is the acceleration due gravity
We need to find how far (horizontally) the cannonball has traveled before landing. This means we need to find the maximum distance in the x-component, let's call it and this occurs when .
So, firstly we will find the time with (2):
(3)
Rearranging the equation:
(4)
(5)
This is a <u>quadratic equation</u> (also called <u>equation of the second degree</u>) of the form , which can be solved with the following formula:
(6)
Where:
Substituting the known values:
(7)
Solving (7) we find the positive result is:
(8)
Substituting this value in (1):
(9)
This is the horizontal distance the cannonball traveled before it landed on the ground.