The human eye is sensitive to yellow-green light having a frequency of about 5.5x 10^14 Hz (a wavelength of about 550 nm) what i
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Answer:
The Magnifying power of a telescope is
Explanation:
Radius of curvature R = 5.9 m = 590 cm
focal length of objective =
⇒ =
⇒ = 295 cm
Focal length of eyepiece = 2.7 cm
Magnifying power of a telescope is given by,
therefore the Magnifying power of a telescope is
<h2>Time needed is 2545.45 seconds.</h2>
Explanation:
We know equation for power
Here we need to find time when for a 22 kW steam engine to do 5.6 × 10⁷ J of work.
So
Work = 5.6 × 10⁷ J
Power = 22 kW = 22 x 10³ W
Substituting
Time needed is 2545.45 seconds.