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slavikrds [6]
3 years ago
15

100 POINTSSSS PLEASE HELP

Physics
2 answers:
Ahat [919]3 years ago
8 0

renewable resources primarily used to produce electricity wuld be those power plants that are big like a dam for hydroelectric, wind turbine for electric generation, geothermal power plant, and solar farm for electricity.


lara31 [8.8K]3 years ago
4 0
Wood, wind, sunshine,geothermal energy, biomass and water 
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Which of the following statements about motion are true? Select all that apply.
Blababa [14]

Answer:

A, C, D

Explanation:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

and according to Newton's 4th law: An object that is at rest will stay at rest unless a force acts upon it. An object that is in motion will not change its velocity unless a force acts upon it.

4 0
3 years ago
When a student stands on a rotating table,the frictional force exerted on the student by the table is?
lakkis [162]

Answer:

Less

Explanation:

because static friction is more than rolling friction

7 0
3 years ago
A car accelerates from 20 m\s to 30 m\s in 2 seconds. What is the average acceleration of the car?
Morgarella [4.7K]

Answer: Acceleration =5m/s^2

Explanation:

3 0
2 years ago
A hockey puck with a mass of 0.16 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper has a mass of 120 kg an
Ainat [17]

Answer:

Explanation:

Momentum is the product of mass of a body and its velocity.

Given the mass of the puck m1 = 0.16kg

velocity of the puck v1 = 40m/s

Given the mass of the goalkeeper m2 = 120kg

velocity of the goalkeeper v2= 0m/s (goal keeper at rest)

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:

m1v1 + m2v2 (their momentum will be added since they collide)

= 0.16(40) + 120(0)

= 0.16(40) + 0

= 6.4kgm/s

Let us calculate their common velocity using the conservation of momentum formula;

m1u1 + m2u2 = (m1+m2)v

6.4 = (0.16+120)v

6.4 = 120.16v

v = 6.4/120.16

v = 0.053m/s

Hence after collision, both objects move at a velocity of 0.053m/s

Momentum of the puck after collision = m1v

Momentum of the puck after collision = 0.16*0.053m/s

Momentum of the puck after collision = 0.0085kgm/s

Momentum of the keeper after collision = m2v

Momentum of the keeper after collision = 120*0.053m/s

Momentum of the keeper after collision = 6.36kgm/s

From the calculation above, it can be seen that the keeper has the greater momentum after the puck was caught since the momentum of the keeper after collision is greater than that of the puck

4 0
3 years ago
Give 2 examples of each major cell group?
lutik1710 [3]

Answer:

The Prokaryotic Cells and The Eukaryotes

5 0
3 years ago
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