p = mv so this question pertains to conservation of momentum.
The momentum of the car is 1320*12 = 15840kgms^-1
For the sake of easiness and the fact negatives are annoying, I will assume east to be positive.
So we know 9.4m - 15840 = (1320+m)*1.5
9.4m - 15840 = 1980+1.5m
Rearranging to solve for m
7.9m = 17820
m = 2255.70 = 2300kg to 2sf
Non ferrous metals such as aluminum, germanium, wood to wood contact, spinning pure distilled water, trees
Answer:
2.14 s
Explanation:
The period is the time for 1 revolution. If it takes 21.4 seconds to make 10 revolutions, then it takes 2.14 seconds to make 1 revolution.
You can show this with a proportion:
t / 1 rev = 21.4 s / 10 rev
t = 2.14 s
What ways do you see diversity celebrated around you and in what ways can we all do a better job of celebrating diversity?
Ans- Visit an exhibition or a museum dedicated to other cultures.
Learn about another religion.
Plan an international movie night.
Listen to music from a different culture.
Play a game or take up a sport from a different culture (karate, cricket,
Invite a friend and cook traditional food.
If you could have dinner with any historical figure, who would you choose and why?
Ans- My younger self. Think about it. If you could have dinner with your younger self, you could easily become the smartest person in history.
Can you share a fun fact about yourself?
Ans- Yes, from 1 breadth I cam swim from 1 end to another
Answer:
The answer is below
Explanation:
1.5 - kΩ resistor is connected to an AC voltage source with an rms voltage of 120 V. (a) What is the maximum voltage across the resistor? (b) What is the maximum current through the resistor? (c) What is the rms current through the resistor? d) What is the average power dissipated by the resistor?
Solution:
The rms value of current and voltage shows the alternating quantity of the voltage and current.
Given that V(rms) = 120 V, R = 1.5 kΩ
a) The maximum voltage across the resistor is given as:
b) The maximum current through the resistor is:
c) The rms current through the resistor is:
d) The average power dissipated by the resistor is: