What is the pOH value of 0.0000877 M HCL

Choose the best answer below. Which of the following reactions will have the largest equilibrium constant at 298 K?

Maurinko [17]

Answer:

Explanation:

Relation between ΔG₀ and K ( equilibrium constant ) is as follows .

lnK = - ΔG₀ / RT

$K = e^{-\frac{\triangle G_0}{RT}$

The value of R and T are same for all reactions .

So higher the value of negative ΔG₀ , higher will be the value of K .

Mg(s) + N₂0(g) → MgO(s) + N₂(g)

has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .

5 0

3 years ago

1. Discuss briefly system and surrounding using suitable examples, highlighting heat transfers. 14 marks

lisabon 2012 [21]

A system is a part of the physical universe defined arbitrarily for observation purposes.

Boundaries are a part of the physical universe that are around the system.

In a scientific sense, a system is a part of the physical universe whose boundaries, that is, the limit between the system and its surroundings, are defined arbitrarily for observation purposes.

A system contains at least a model, represented in a phenomenological way, and it can be isolated (no mass nor energy interactions), closed (no mass interactions) or open.

The surroundings are a part of the physical universe that are around the system.

An example is a coffee-maker, where coffee-maker the system and air represents the surroundings, the coffee-maker receives energy from a heat source to warm up itself and releases part of such energy to the air.

We kindly invite to check this question on systems and surroundings: brainly.com/question/6044762

3 0

2 years ago

What are the basic building blocks of matter?

Naddik [55]

Elements because elements make up atoms which make up everything

8 0

3 years ago

Read 2 more answers

If you need an object to move a further distance, how would you adjust the force?

Alborosie

Answer:

slingshot or throw it

Explanation:

4 0

2 years ago

Read 2 more answers

Three 1.0-l flasks, maintained at 308 k, are connected to each other with stopcocks. initially the stopcocks are closed. one of

Licemer1 [7]

Answer:

0.6103 atm.

Explanation:

We need to calculate the vapor pressure of each component after the stopcocks are opened.

Volume after the stopcocks are opened = 3.0 L.

1) For N₂:

P₁V₁ = P₂V₂

P₁ = 1.5 atm & V₁ = 1.0 L & V₂ = 3.0 L.

P₂ of N₂ = P₁V₁ / V₂ = (1.5 atm) (1.0 L) / (3.0 L) = 0.5 atm.

2) For H₂O:

Pressure of water at 308 K is 42.0 mmHg.

we need to convert from mmHg to atm: (1.0 atm = 760.0 mmHg).

P of H₂O = (1.0 atm x 42.0 mmHg) / (760.0 mmHg) = 0.0553 atm.

We must check if more 2.2 g of water is evaporated,

n = PV/RT = (0.0553 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.00656 mole.

m = n x cmolar mass = (0.00656 mole) (18.0 g/mole) = 0.118 g.

It is lower than the mass of water in the flask (2.2 g).

3) For C₂H₅OH:

Pressure of C₂H₅OH at 308 K is 102.0 mmHg.

we need to convert from mmHg to atm: (1.0 atm = 760.0 mmHg).

P of C₂H₅OH = (1.0 atm x 102.0 mmHg) / (760.0 mmHg) = 0.13421 atm.

We must check if more 0.3 g of C₂H₅OH is evaporated,

n = PV/RT = (0.13421 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.01594 mole.

m = n x molar mass = (0.01594 mole) (46.07 g/mole) = 0.7344 g.

It is more than the amount in the flask (0.3 g), so the pressure should be less than 0.13421 atm.

We have n = mass / molar mass = (0.30 g) / (46.07 g/mole) = 0.00651 mole.

So, P of C₂H₅OH = nRT / V = (0.00651 mole) (0.082 L.atm/mole.K) (308.0 K) / (3.0 L) = 0.055 atm.

So, total pressure = P of N₂ + P of H₂O + P of C₂H₅OH = 0.5 atm + 0.0553 atm + 0.055 atm = 0.6103 atm.

3 0

3 years ago