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Debora [2.8K]
3 years ago
15

There are two naturally occurring isotopes of boron. 10 B has a mass of 10.0129 u. 11 B has a mass of 11.0093 u. Determine the a

bundance of each isotope
Chemistry
1 answer:
Vanyuwa [196]3 years ago
5 0
<h2>Natural Abundance for 10B is 19.60%</h2>

Explanation:

  • The natural isotopic abundance of 10B is 19.60%.
  • The natural isotopic abundance of 11B is 80.40%.
  • The isotopic masses of boron are 10.0129 u and 11.009 u respectively.

For calculation of abundance of both the isotopes -

Supposing it was 50/50, the average mass would be 10.5, so to increase the mass we need a more percentage of 11.

Determining it as an equation -

10x + 11y= 10.8

x+y=1 (ratio)

10x + 10y = 10

By taking the denominator away from the numerator

we get;

y = 0.8

x + y = 1

∴ x = 0.2

To get percentages  we need to multiply it by 100

So, the calculated abundance is 80% for 11 B and 20% 10  B.

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ZnS (s) + AIP(s) → AI₂S₂(s) + Zn P₂(s)
Allisa [31]

Answer:

3 ZnS (s) + 2 AIP(s) ---> AI₂S₃(s) +  Zn₃P₂(s)

Explanation:

I believe you are asking for this reaction to be balanced. However, after looking more closely, those are not the products that would be created from the reactants. Assuming this is a double-displacement reaction, and taking the most common charges of the ions into consideration, the actual products would be AI₂S₃(s) + Zn₃P₂(s). I apologize if I assumed incorrectly.

For an equation to be balanced, there needs to be the same amount of each element on both sides of the equation.

The unbalanced equation:

ZnS (s) + AIP(s) ---> AI₂S₃(s) + Zn₃P₂(s)

<u>Reactants</u>: 1 zinc, 1 sulfur, 1 aluminum, 1 phosphorus

<u>Products</u>: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

As you can see, there is an unequal amount of each element on the reactants and products side. To balance the equation, coefficients in front of the compound(s) will be necessary.

The balanced equation:

3 ZnS (s) + 2 AIP(s) ---> AI₂S₃(s) +  Zn₃P₂(s)

<u>Reactants</u>: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

<u>Products</u>: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

3 0
2 years ago
A steel container filled with H₂ gas is at a pressure of 6.5 atm and a temperature of 22°C. If the container is placed near a fu
Yuki888 [10]

Answer: The new pressure is 7.1 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=6.5atm\\T_1=22^0C=(22+273)K=295K\\P_2=?\\T_2=50^0C=(50+273)K=323K

Putting values in above equation, we get:

\frac{6.5}{295}=\frac{P_2}{323}\\\\P_2=7.1

Hence, the new pressure is 7.1 atm

8 0
3 years ago
Which of the procedures, if either, is more accurate when making a 1/501/50 dilution of a solution? Transfer 1 mL1 mL with a pip
nikitadnepr [17]

Full question:

First of all, bear in mind that this question is incomplete. Here is the full question:

  • Which of the procedures, if either, is more accurate when making a 1/50 dilution of a solution?

a) Transfer 1 mL with a pipet into a 50-mL volumetric flask.

b) Transfer 20 mL with a pipet into a 1-L volumetric flask.

c) Both procedures have the same accuracy.

  • How can the accuracy of either procedure be improved?

a) Use an Erlenmeyer flask instead of a volumetric flask.

b) Use a graduated cylinder instead of a pipet for the transfer.

c) Calibrate each piece of glassware.

d) Instead of using a 1/50 dilution to make the solution, weigh out the material on a balance and transfer ir directly to the volumetric flask.

Answer:

1) c) Both procedures have the same accuracy.

2) c) Calibrate each piece of glassware.

Explanation:

1) Given that the 1/50 relation is maintained whether we pour 1 mL into a 50-mL volumetric flask or we transfer 20 mL with a pipet into a 1-L volumetric flask, both procedures have the same accuracy (because in both procedures we are using volumetric glassware).

When we want the most exact result possible, we need to calibrate the volumetric glassware used (bear in mind that the only volumetric glassware is the buret, the volumetric flask, the micropipet and the pipet). This is usually done measuring the mass of water poured by the recipient or contained in it, and using the density of that liquid to convert mass into volume. In this way is possible, for example, to determine that a pipet poured 10.016 mL and not 10.000 mL.

3 0
3 years ago
1.Build or draw the Lewis structure for each of the molecules listed below.
bagirrra123 [75]
This may help you

Allright for <span><span>H2</span>O:</span> - The central atom is? --> the oxygen atom - How many atoms are bonded to the central atom? --> 2 hydrogen atoms - How many lone pairs of electrons are on the central atom? --> O has 6 electrons and has 2 single bonds, so 2 pairs - How many single bonds are there in this molecule? --> 2 - How many multiple bonds (double and/or triple) are there in this molecule? --> none For each of your molecules, answer the following questions: 1. Determine the electronegativity between the atoms of each molecule. Electronegativity O = 3.44 Electronegativity H = 2.20 3.44-2.20=1.24, so the electronegativity between O and H = 1.24 2. Identify the bond as either ionic or covalent. Electronegativity of 0.0-1.7 = covalent Electronegativity of 1.7-3.3 = ionic So it's a covalent bond 3. State whether the molecule is polar or non polar. Electronegativity of 0.5-1.7= polar covalent 4. Identify the structure as having hydrogen bonding, dipole-dipole moments or London dispersion forces (LDF). <span><span>H2</span>O</span><span> = hydrogen bonding</span>
5 0
3 years ago
Diazomethane has the molecular formula CH2N2. Draw the preferred Lewis structure for diazomethane and assign formal charges to a
Alja [10]

Answer:

See explanation

Explanation:

We define the formal charge on an atom in a molecule as the charge it carries assuming that electrons in all chemical bonds of the molecule were shared equally between atoms irrespective of the electronegativity of each atom.

The formula for calculating the formal charge on an atom in a molecule is;

Formal Charge = [number of valence electrons on neutral atom] – [(number of lone electron pairs) + (½ number of bonding electrons)] ·

The formal charge on the two nitrogen atoms in diazomethane is obtained as follows;

Middle nitrogen atom = 5 – 8/2 – 0 = +1

Last nitrogen atom = 5 – 4/2 – 4 = –1

The Lewis structure of the molecule is shown in the image attached.

8 0
3 years ago
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