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3 years ago

Which of the following is a mixture

2 answers:

5 0

Much of the gold that is mined is actually from " gold ore " rather than actual gold specimens.
The ore is often brown, iron stained rock or massive white quartz, and usually contains only minute traces of gold. To extract the gold, the ore is crushed, then the gold is separated from the ore by various methods.

So your answer is. "Gold Ore" is a mixture.

I hope this helps.

IgorLugansk [536]3 years ago

4 0

Gold Ore is a mixture.

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What is the definition of Jupiter

Stolb23 [73]

In astronomy, the largest planet recorded in the solar system; the fifth major planet from the sun. Jupiter is largely composed of gases. It is named after the ruler of the Roman Gods. You can find this under Mythology and Folklore. You can see Jupiter from Earth.

*Since my first comment was deleted for supposedly being copied and pasted(which it wasn't) I'm leaving this here. It was NOT copied and pasted!!*

8 0

3 years ago

An acid would __________. Group of answer choices turn red litmus paper blue react with bases to create a neutral solution react

Wewaii [24]

Answer:

blue react with bases to create a neutral solution

Explanation:

A strong acid will react with a strong base to form a neutral (pH = 7) solution.

3 0

3 years ago

Use the law of conservation of mass to answer the questions. Consider a hypothetical reaction in which A and B are reactants and

shutvik [7]

Answer:

26 grams of D will be produced.

Explanation:

The reaction is given by:

A + B -----> C + D

Mass of A reacted = 21 g

Mass of B reacted = 22 g

Mass of C formed = 17 g

Mass of D formed = m =?

According to law of conservation of mass, the total mass of the reactants used is equal to the total mass of the product formed.

Then:

mass of A reacted + mass of B reacted = mass of C formed + mass of D formed

21 + 22 = 17 + m

m = 26 g

5 0

4 years ago

When iron(III) oxide reacts with hydrochloric acid, iron(III) chloride and water are formed. How many grams of iron(III) chlorid

Aleksandr [31]

Answer: The mass of iron (III) chloride produced is 14.81 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For iron(III) oxide:

Given mass of iron(III) oxide = 10.0 g

Molar mass of iron(III) oxide = 159.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of iron(III) oxide}=\frac{10.0g}{159.7g/mol}=0.0626mol$

For hydrochloric acid:

Given mass of hydrochloric acid = 10.0 g

Molar mass of hydrochloric acid = 36.5 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid}=\frac{10.0g}{36.5g/mol}=0.274mol$

The chemical equation for the reaction of iron (III) oxide and hydrochloric acid follows:

$Fe_2O_3+6HCl\rightarrow 2FeCl_3+3H_2O$

By Stoichiometry of the reaction:

6 moles of hydrochloric acid reacts with 1 mole of iron (III) oxide

So, 0.274 moles of hydrochloric acid will react with = $\frac{1}{6}\times 0.274=0.0456mol$ of iron (III) oxide

As, given amount of iron (III) oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

6 moles of hydrochloric acid produces 2 moles of iron (III) chloride

So, 0.274 moles of hydrochloric acid will produce = $\frac{2}{6}\times 0.274=0.0913moles$ of iron (III) chloride

Now, calculating the mass of iron (III) chloride from equation 1, we get:

Molar mass of iron (III) chloride = 162.2 g/mol

Moles of iron (III) chloride = 0.0913 moles

Putting values in equation 1, we get:

$0.0913mol=\frac{\text{Mass of iron (III) chloride}}{162.2g/mol}\\\\\text{Mass of iron (III) chloride}=(0.0913mol\times 162.2g/mol)=14.81g$

Hence, the mass of iron (III) chloride produced is 14.81 grams

7 0

3 years ago

A total of 2.00 mol of a compound is allowed to react with water in a foam coffee cup and the reaction produces 173 g of solutio

Nataly_w [17]

Answer: (4.184 J/gÂ·Â°C) x (185 g) x (24.70 - 21.00)âC = 2863.948 J = 2.86 kJ (2.86 kJ) / (2.00 mol) = 1.43 kJ/mol

7 0

4 years ago