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vlada-n [284]
3 years ago
6

A hypodermic needle consists of a plunger of circular cross-section that slides inside a hollow cylindrical syringe. when the pl

unger is pushed, the contents of the syringe are forced through a hollow needle (also of circular cross-section). if a 4.0-n force is applied to the plunger and the diameters of the plunger and the needle are 1.2 cm and 2.5 mm, respectively, what force, in n, is needed to prevent fluid flow at the needle?
Physics
1 answer:
Blababa [14]3 years ago
4 0
The fluid that is being passed through the syringe and needle is incompressible, which means that it will transmit pressure equally. Therefore, the pressure on the plunger will be equivalent to the pressure on the needle. We also know that:

Pressure = Force / Area

Pressure on plunger = 4 / (π*(0.012/2)²)
Pressure on plunger = 35.4 kPa
Pressure on needle = 35.4 kPa

35.4 kPa = F / (4 / (π*(0.0025/2)²)
F = 0.17 N

The force on the needle is 0.17 N
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Explanation:

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the act of inferring (to derive by reasoning). Observation = an act or instance of noticing or perceiving.

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3 years ago
Are There some sounds for which we are all deaf
lana66690 [7]

Answer: Infrasound is the span of low-frequency sounds below 20 Hz that fall below the hearing range of humans. While these sounds escape our ears, scientific instruments can detect them—and tell us some interesting things about the planet.

Explanation:

6 0
3 years ago
I have an algorithm that runs in O(N ), where N is the size of the problem. For N = 100, the time for the algorithm to run is 1
hodyreva [135]

Answer:

B) 10 minutes

Explanation:

When the size of the problem is 100 then it takes 1 minute to solve

100\ s=1\ min

So, when the size of the problem is 1 then it takes the following minutes

1\ s=\frac{1}{100}\ min

For when the size of the problem is 1000 we have

1000\ s=\frac{1000}{100}\ min=10\ min

So, it will take 10 minutes to solve the algorithm of size 1000

4 0
3 years ago
A box is pulled 6 meters across the ground at a constant velocity by a horizontally applied force of 50 newtons. At the same tim
Vikentia [17]

Answer:

(a) Friction force = 50 N

(b) Work done by friction = 300 j

(c) Net work done = 0 j

Explanation:

We have given that the box is pulled by 6 meter so d = 6 m

Force applied on the box F = 60 N

We have have given that velocity is constant so acceleration will be zero

So to applied force will be utilized in balancing the friction force

So friction force F_{friction}=50N

Work done by friction force W_{friction}=F_{friction}\times d=50\times 6=300j

Work done by applied force W=F\times d=50\times 6=300j

So net work done = 300-300 = 0 j

7 0
3 years ago
A playground slide is inclined 40°. If a boy with a mass of 32 kg slides down for -3meters. How much work is done by gravity on
telo118 [61]

Answer:

the work done by gravity on the boy is 604.62 J

Explanation:

Given;

distance the boy slides, d = 3 m

angle of inclination of the playground, θ = 40⁰

mass of the boy, m = 32 kg

The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.

The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.

sin \theta = \frac{opposite }{hypotenuse} \\\\sin \theta = \frac{h}{d} \\\\h = dsin\theta\\\\h = 3 \times sin(40^0)\\\\h = 1.928 \ m

The work done by gravity on the boy is calculated as;

W = P.E = mgh

             = 32kg x 9.8m/s² x 1.928m

             = 604.62 J

Therefore, the work done by gravity on the boy is 604.62 J

8 0
3 years ago
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