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diamong [38]
3 years ago
13

Jack tries to place magnets on his refrigerator at home, but they won’t stick. What could be the reason?

Physics
2 answers:
zzz [600]3 years ago
6 0
Either it don't have a magnetic field around them or it's not a sheet steel door
Ivahew [28]3 years ago
4 0
The refrigerator door is probably made of a non-magnetic material,
such as wood, stone, cardboard, plastic, copper, aluminum, or jello.
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High friction materials​
Harrizon [31]

Answer:

For the dry and static friction materials, some of these are Rubber, Aluminum, Gold, Platinum,

Explanation:

High friction materials has higher coefficient of friction (COF).

7 0
3 years ago
5. A 1.2 m guitar string is under a tension of 888 N. The waves produced on the string (when
Usimov [2.4K]
I don’t even know tbh
4 0
3 years ago
You are traveling at 14 m/s for 20 seconds. What is your displacement?
enyata [817]

Velocity = 14 m/s

Time = 20 s

Displacement = Velocity×Time = (14×20) m = 280 m

The displacement is 280 m towards the direction of motion.

5 0
3 years ago
Read 2 more answers
A delivery truck travels with a constant velocity up an 8 slope. A 60 kg box sits on the floor of the truck and, because of sta
Blababa [14]

Explanation:

Given that,

The slope of the ramp, \theta=8^{\circ}

Mass of the box, m = 60 kg

(a) Distance covered by the truck up the slope, d = 300 m

Initially the truck moves with a constant velocity. We know that the net work done on the box is equal to 0 as per work energy theorem as :

W=\dfrac{1}{2}m(v^2-u^2)=0

u and v are the initial and the final velocity of the truck

(b) The work done on the box by the force of gravity is given by :

W=Fd\ cos\theta

Here, \theta=90+8=98^{\circ}

W=mgd\ cos\theta

W=60\times 9.8\times 300\ cos(98)

W = -24550.13 J

(c) What is the work done on the box by the normal force is equal to 0 as the angle between the force and the displacement is 90 degrees.

(d) The work done by friction is given by :

W_f=-W

W_f=24550.13\ J

Hence, this is the required solution.

6 0
3 years ago
You are given a vector in the xy plane that has a magnitude of 84.0 units and a y-component of -67.0 units.
melomori [17]

Answer:

Explanation:

a)Magnitude = \sqrt{(x1-y2)^{2}  + (x1-x2)^{2} }

84=\sqrt{(0- (-67))^{2}  + (x-0)^{2} }

x= +50.67 or -50.67 units

b) We are given that the resultant is entirely in the -ve x direction which means that the y-component of the resultant is 0; It means that the y-component of the next vector = -ve of the y component of the initial vector i.e 67.

To make the magnitude 80 units in the negative x direction where the y component is 0, the x component must be -130.67(-50.67 - 80) as the x component is + 50.67units.

Magnitude = \sqrt{(0- (67))^{2}  + (-130.67)^{2} } = 146.85 units

c) The direction vector = 67/146.85 i  - 130.67/146.85 j where i corresponds to the vector in y direction and j corresponds to the vector in x direction. Or this vector is at an angle of 180 - Tan^{-1}(67/130.67)degrees i.e 152.85 degrees from the +ve x-axis.

5 0
3 years ago
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