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svp [43]
3 years ago
15

Where is the electric field closest to uniform? inside a circle described by a point charge at its center between parallel plate

s of equal charge and equal magnitude inside a circle described by identical, evenly-spaced point charges around the circumference between parallel plates of equal charge and opposite magnitude
Physics
1 answer:
Soloha48 [4]3 years ago
5 0

1. Inside a circle described by a point charge at its center will not be uniform field as a point charge field will change with distance where as we move away the field strength will go down.

2. between parallel plates of equal charge and equal magnitude will have zero electric field because both plates are of same charge so electric field of both plates will cancel each other.

3. inside a circle described by identical, evenly-spaced point charges around the circumference field will be zero as all charges are distributed uniformly and they cancel the field effect of each other.

4. between parallel plates of equal charge and opposite magnitude field will be nearly uniform as the two charges are opposite in nature and equal in magnitude so the effect will be added.

So answer of the above will be between parallel plates of equal charge and opposite magnitude

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2.77 * 10^5 m/s

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3 years ago
What’s the acceleration if the average velocity is 3.5 and the time is 8.7
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3 years ago
How much work is done when a 214 newton force pushes a sleeping cow 37m across a field.
nata0808 [166]
Hello!

Answer: 
7918 J

Explanation:

We are assuming that the floor (field) is completely horizontal since there's no information about that in the statement. 

We are going to use the following formula:

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F=214 N
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4 0
3 years ago
A delivery truck travels 2.8 km North, 1.0 km East, and 1.6 km South. The final displacement from the origin is ___km to the ___
34kurt

Answer:

The final displacement from the origin is <u>1.6</u> km to the <u>NE</u>

Explanation:

The directions in which the delivery truck travels are;

1) 2.8 km North = 2.8·\hat j, in vector form

2) 1.0 km East = 1.0·\hat i, in vector form

3) 1.6 km South = -1.6·\hat j, in vector form

Therefore, to find the final displacement, Δx, of the delivery truck, we add the individual displacements as follows;

Final displacement, Δd = 2.8·\hat j + 1.0·\hat i +(-1.6·\hat j) = 1.2·\hat j + 1.0·\hat i

Final displacement, = 1.0·\hat i + 1.2·\hat j

Where;

Δx = The displacement in the x-direction = 1.0·\hat i

Δy = The displacement in the y-direction = 1.2·\hat j

The magnitude of the resultant displacement vector is given as follows

\left | d \right | = √((Δx)² + (Δy)²) = √(1² + 1.2²) ≈ 1.6 (To the nearest tenth)

The magnitude of the resultant displacement vector ≈ 1.6 km

The direction of the resultant vector is positive for both the east and north direction, therefore, the direction of the resultant vector = NE

Therefore, the resultant displacement of the delivery truck is approximately 1.6 km, NE from the origin.

3 0
3 years ago
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