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svp [43]
4 years ago
15

Where is the electric field closest to uniform? inside a circle described by a point charge at its center between parallel plate

s of equal charge and equal magnitude inside a circle described by identical, evenly-spaced point charges around the circumference between parallel plates of equal charge and opposite magnitude
Physics
1 answer:
Soloha48 [4]4 years ago
5 0

1. Inside a circle described by a point charge at its center will not be uniform field as a point charge field will change with distance where as we move away the field strength will go down.

2. between parallel plates of equal charge and equal magnitude will have zero electric field because both plates are of same charge so electric field of both plates will cancel each other.

3. inside a circle described by identical, evenly-spaced point charges around the circumference field will be zero as all charges are distributed uniformly and they cancel the field effect of each other.

4. between parallel plates of equal charge and opposite magnitude field will be nearly uniform as the two charges are opposite in nature and equal in magnitude so the effect will be added.

So answer of the above will be between parallel plates of equal charge and opposite magnitude

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The current in a series circuit is 19.3 A. When an additional 7.40-Ω resistor is inserted in series, the current drops to 13.4 A
Bogdan [553]

Answer:

16.8ohms

Explanation:

According to ohm's law which states that the current passing through a metallic conductor at constant temperature is directly proportional to the potential difference across its ends.

Mathematically, V = IRt where;

V is the voltage across the circuit

I is the current

R is the effective resistance

For a series connected circuit, same current but different voltage flows through the resistors.

If the initial current in a circuit is 19.3A,

V = 19.3R... (1)

When additional resistance of 7.4-Ω is added and current drops to 13.4A, our voltage in the circuit becomes;

V = 13.4(7.4+R)... (2)

Note that the initial resistance is added to the additional resistance because they are connected in series.

Equating the two value of the voltages i.e equation 1 and 2 to get the resistance in the original circuit we will have;

19.3R = 13.4(7.4+R)

19.3R = 99.16+13.4R

19.3R-13.4R = 99.16

5.9R = 99.16

R= 99.16/5.9

R = 16.8ohms

The resistance in the original circuit will be 16.8ohms

5 0
3 years ago
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Answer:

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Explanation:

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a = 9 × 10^5 m/s^2

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Try This Method(substitute your values)
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3 years ago
A circuit has a voltage drop of 12.0 V across a 30.0 resistor that carries a current of 0.400 A. What is the power used by the r
Aloiza [94]

Option ( c ) is correct.

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7 0
3 years ago
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