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umka2103 [35]
3 years ago
12

Which of the following is equal to distance divided by time?

Physics
2 answers:
givi [52]3 years ago
4 0

To find <em>Speed </em>you divide distance by time.

Reasoning:

Displacement is the change in an object's position from the origin.

To find Acceleration you use the equation a=v^2/r

To find Velocity you divide the distance by the time it takes to travel that distance, then you add your direction to it.

<em>To find speed you use distance is over time</em>


topjm [15]3 years ago
3 0

The answer is D. Speed. The equation for speed is distance/time. For example, If I were to travel 60 miles in two hours, to find the average speed, you would divide 60 by 2, to get 30 miles/hour.

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An object initially at rest experiences an acceleration
lidiya [134]

Answer:

1.4m/s

Explanation:

Average velocity is the total distance covered divided by the total time taken.

 Average velocity  = \frac{total distance }{time }  

 Total time taken  = 5s + 6s  = 11s

The first distance covered  = velocity x time  = 1.4 x 5 = 7m

     second distance covered  = velocity x time  = 1.4 x 6  = 8.4m

So;

  Average velocity  = \frac{7 + 8.4}{11}    = 1.4m/s

5 0
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A fan that is switched on for 1 minute uses 500 W usefully but also wastes 300 W through the emission of sound and heat. What's
koban [17]

Explanation:

Efficiency is defined as the ratio between the useful output over the total amount consumed. E = \frac{useful}{total}

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In deep space (no gravity), the bolt (arrow)
salantis [7]

t  = 0.527 s

<u>It accelerates for 0.527 s.</u>

<u>Explanation:</u>

We use the formula:

v = u+at

Given:

v = 106 m/s

u = 0 (since no gravity)

a=201 \mathrm{m} / \mathrm{s}^{2}

So applying the formula,

v = u+at

106 = 0 + 201t

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4 0
3 years ago
Help! <br><br><br>I'm not sure my answer is correct.<br><br><br>Problem is attached!​
kaheart [24]
  • Let G be xN

\\ \sf\longmapsto x-20=30

\\ \sf\longmapsto x=30+20

\\ \sf\longmapsto x=50N

Option B

3 0
3 years ago
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Problema en la cual aplicaste velocidades, impulso, conservación del movimiento y de la energía.
Kazeer [188]
Huh huh what? ¿Can’t you translate?
6 0
3 years ago
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