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satela [25.4K]
3 years ago
6

high temperature in metals leads to decrease in conductivity while increase in Temperature conductivity in semiconductor increas

es, why?​
Physics
1 answer:
Elza [17]3 years ago
8 0

Answer:

.

The conductivity of metals decreases with increasing temperature because of thermal agitation of the conduction electrons, which impedes their movement in response to an electric field and therefore lowers the drift velocity.

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A feverish student weighing 75,000 grams was immersed in 400,000 g of water at 4.0°C to try to reduce the fever. The student's b
schepotkina [342]
Heat lost = (75000)(3.77)(3) = 848250 J = heat gained by water

848250 = 400000(4.814)(T)
T = 0.507 C
4 + 0.507 = 4.507 C
3 0
3 years ago
A uniform cylinder of radius 25 cm and mass 27 kg is mounted so as to rotate freely about a horizontal axis that is parallel to
Alisiya [41]

Answer:

Explanation:

                                                     STEP 1

<u>Given</u>

Radius of cylinder = r = 25cm, 2.5m

mass = 27kg

cylinder is mounted so as to rotate freely about a horizontal axis that is parallel to and 60cm to the central logitudinal axis of the cylinder

height = 0.6m

<u>part 1</u>

The cylinder is mounted so as to rotate freely about a horizontal axis tha is paralle to 60cm from the central longitudinal axis of then cylinder. The rotational inertia of the cylinder about the axis of rotation is given by

<em>I = Icm + mh²</em>

<em>∴ I = 1/2mr² + mh² = 1/2x27x (0.5)² + 20  x  (0.6)²</em>

<em>I=13.09kg.m²</em>

where

<em>I</em>cm is the rotational inertia of the cylinder about its central axis

m is the mass of the cylinder

h is the distance between the axis of the rotation and the central axis of the cylinder

r is the radius of the cylinder

<em>                                        </em><em> I=13.09kg.m²</em>

<em>part2</em>

<em>from the conservation of the total mechanical energy of the meter stick, the change in gravitational potential energyof the meter stick plus the change in kinetic energy must be zero</em>

<em>Δk + Δu = 0</em>

<em>1/2 </em>I(w²-w²) = Ui-Uf

1/2 x 13.09w² = mgh

∴w=√20 x 9.8 x 0.6/(1/2 x 13.09) =117.6/6.5

w=18.09rad/s

5 0
3 years ago
Titan is the only moon in the solar system with a significant atmosphere. which planet does titan orbit?
sveticcg [70]
"Saturn". It is largest moon of Saturn.

In short, Your Answer would be Option B

Hope this helps!
6 0
3 years ago
A disk of radius 10 cm is pulled along a frictionless surface with a force of 16 N by a string wrapped around the edge. At the i
drek231 [11]

Answer:

t = 0.2845Nm (rounded to 4 decimal places)

Explanation:

The disk rotates at a distance of an arc length of 28cm

Arc length = radius × central angle × π/180

28cm = 10cm × central angle × π/180

Central angle = \frac{28}{10} × 180/π ≈ 160.4°

Torque (t) = rFsin(central angle) , where F is the applied force

Radius in meters = 10/100 = 0.1m

t = 0.1m × 16N × sin160.4°

t = 0.2845Nm (rounded to 4 decimal places)

8 0
3 years ago
An object is 70 um long and 47.66um wide. how long and wide is the object in km?​
Ganezh [65]

Answer:

length =  7*10^(-8)km

width = 4.666*10^(-8) km

Explanation:

We know that:

1 μm = 1*10^(-6) m

and

1km = 1*10^3 m

or

1m = 1*10^(-3) km

if we replace the meter in the first equation, we get:

1 μm = 1*10^(-6)*1*10^(-3) km

1 μm = 1*10^(-6 - 3)km

1 μm = 1*10^(-9)km

Now with this relationship we can transform our measures:

Length: 70 μm is 70 times 1*10^(-9)km, or:

L = 70*1*10^(-9)km = 7*10^(-8)km

And for width, we have 47.66um, this is 46.66 times 1*10^(-9)km, or:

W = 46.66*1*10^(-9)km = 4.666*10^(-8) km

7 0
2 years ago
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