What is produced on the top of the pool of water by the mutual attraction between water molecules

1 answer:

6 0

The thing that is produced on the top of the pool of water by the mutual attraction between water molecules is known as surface tension. The surface tension of water is actually what gives water the elastic tendency and allows the water to acquire the least amount of surface area possible. This surface tension is the reason why insects denser than water can slide on the surface of the water.

You might be interested in

Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. K2SO4 NH4I CoCl3

katrin [286]

The substance that releases the greatest amount of ions will have the greatest attractive forces within its solution, resulting in a reduced freezing point.
K₂SO₄ yields 3 ions
NH₄I yields 2 ions
CoCl₃ yields 4 ions

Freezing points:
CoCl₃ < K₂SO₄ < NH₄I

8 0

3 years ago

Another name for a "oxidation-reduction" reaction is

anzhelika [568]

Redox (red for reduction and ox for oxidation)

8 0

3 years ago

Is h2c2o4 an Arrhenius base or arrhenius acid

maksim [4K]

Answer:
Oxalic Acid is and Arrhenius Acid.

Explanation:
According to Arrhenius Theory of acid and base, "Acid is any substance which when dissolved in water produces H⁺ Ions".

Therefore, Oxalic Acid is a diprotic substance, which is capable of donating protons in water. This acidity of oxalic acid can be dedicated to the stability of conjugate base, this stability comes from resonance of the negative charges on Oxalate ion. Below reaction shows the dissociation of Oxalic Acid into Protons and Oxalate Ion.

6 0

3 years ago

Using Equation (10), calculate [Ag+] in the cell, where it is in equilibrium with 1 M Cl- ion. (Ecell in Equation (10) is the ne

mixer [17]

Answer:

7.16x10⁻⁸M = [Ag+]

Explanation:

Using the equation:

E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)

Where E⁰= 0.4249V

E(Cell) = -(-0.0019V) -Measured value-

[Cu2+] = 1M

Replacing:

0.0019V = 0.4249V - 0.0592/2 • log (1M/[Ag+]²)

-0.423V = - 0.0296 • log (1M/[Ag+]²)

14.29 = log (1M/[Ag+]²)

1.95x10¹⁴ = 1M / [Ag+]²

[Ag+]² = 5.12x10⁻¹⁵M

7.16x10⁻⁸M = [Ag+]

5 0

2 years ago

Ethical Behavior Worksheet Situation 1. You are taking a very difficult chemistry course, which you must pass to maintain your s

krok68 [10]

Answer:

I would not accept it.

Explanation:

Although it is tempting to accept the janitor's offer and save the scholarship, which is not easy to get, I would not accept his offer, as I do not believe in victories based on dishonesty and would be heavy on conscience if I did the opposite. Obviously, I would not like to lose my scholarship and for that reason, I would look for other ways that would be honest and help me improve my grade. If I could not improve and lose the scholarship, I would be extremely sad, but I would be at peace with my conscience.

4 0

3 years ago