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____ [38]
4 years ago
14

Burning magnesium gives us magnesium oxide. This is an example of a reaction.

Chemistry
2 answers:
frez [133]4 years ago
5 0

Answer: -

Oxidation, Oxygen

Explanation: -

Burning of magnesium gives us magnesium oxide.

The chemical symbol of magnesium is Mg.

The chemical symbol of magnesium oxide is MgO.

So, the balanced chemical equation is

2Mg + O2 – 2 MgO.

We see that the element added is O Oxygen. So, the reaction is oxidation.

In oxidation always, oxygen is the common element involved in all chemical reactions of this kind.

VikaD [51]4 years ago
3 0

The given reaction can be represented as,

2Mg (s) + O_{2}(g) ---> 2MgO (s)

In this reaction, two elements (Mg and O_{2}) combine to form a single compound, MgO. Hence, this reaction is an example of chemical combination or synthesis. Here as the element Mg is oxidized in the presence of O_{2} to form MgO. This is referred to as combustion reaction. In combustion reaction, elements or compounds react with oxygen to give their respective oxides.

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Which pair below describes isotopes of the same element?
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B because isotopes have the same number of protons but a different number of neutrons
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A farmer has a 10 acre plot to feed his family. What is the most efficient way to use the plot?
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B. because the meat has more protein and so does the milk
6 0
3 years ago
Compound Y has the elements C, H, N and O. It's exact mass is 91.0425. Answer the following questions. Isotope Exact Mass 1H 1.0
Talja [164]

Answer:

Six C atoms (C₆); five H atoms (H₅); one N atom (N); no O atoms

Explanation:

The rule of 13 states that the formula of a compound is a multiple n of 13 (the molar mass of CH) plus a remainder r.

MF = CₙHₙ₊ᵣ

Y has a molecular mass of 91 u

91/13 =7r0

The formula can't be C₇H₇ because a hydrocarbon must have an even number of H atoms,

The odd mass and the odd number of H atoms make it reasonable to add an N atom and subtract CH₂ (CH₂ = 14):

C₇H₇ + N - CH₂ = C₆H₅N

Check:

6C = 6 × 12.000 = 72.000 u

5H = 5 ×   1.008 =   5.040

1N =  1 × 14.003 =  <u>14.003    </u>

             TOTAL =   91.043 u

This is excellent agreement with the observed mass of 91.0425 u.

There are six  C atoms (C₆)

There are five H atoms (H₅)

There is    one N atom   (N)

There are no   O atoms.

4 0
3 years ago
You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles​ [mol] of 40 grams
Serhud [2]

Answer : The moles of given compound is, 0.064 mole

Explanation : Given,

Mass of given compound = 40 g

Atomic mass of X = 50 amu

Atomic mass of Y = 45 amu

Atomic mass of Z = 10 amu

First we have to calculate the molar mass of given compound.

The given compound formula is, X_5Y_7Z_6

Molar mass of X_5Y_7Z_6 = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)

Molar mass of X_5Y_7Z_6 = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol

Now we have to calculate the moles of given compound.

\text{Moles of given compound}=\frac{\text{Mass of given compound}}{\text{Molar mass of given compound}}

\text{Moles of given compound}=\frac{40g}{625g/mol}

\text{Moles of given compound}=0.064mol

Thus, the moles of given compound is, 0.064 mole

6 0
4 years ago
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