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3 years ago

Burning magnesium gives us magnesium oxide. This is an example of a reaction.

Chemistry

2 answers:

frez [133]3 years ago

5 0

Answer: -

Oxidation, Oxygen

Explanation: -

Burning of magnesium gives us magnesium oxide.

The chemical symbol of magnesium is Mg.

The chemical symbol of magnesium oxide is MgO.

So, the balanced chemical equation is

2Mg + O2 – 2 MgO.

We see that the element added is O Oxygen. So, the reaction is oxidation.

In oxidation always, oxygen is the common element involved in all chemical reactions of this kind.

VikaD [51]3 years ago

3 0

The given reaction can be represented as,

$2Mg (s) + O_{2}(g) ---> 2MgO (s)$

In this reaction, two elements (Mg and $O_{2}$ ) combine to form a single compound, MgO. Hence, this reaction is an example of chemical combination or synthesis. Here as the element Mg is oxidized in the presence of $O_{2}$ to form MgO. This is referred to as combustion reaction. In combustion reaction, elements or compounds react with oxygen to give their respective oxides.

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sineoko [7]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0-L vessel at 300 K. The following equilibriu

tatyana61 [14]

Answer:

[H2] = 0.012 M

[N2] = 0.019 M

[H2O] = 0.057 M

Explanation:

The strategy here is to account for the species at equilibrium given that the concentration of [NO]=0.062M at equilibrium is known and the quantities initially present and its stoichiometry.

2NO(g) + 2H2(g) ⇒ N2(g) + 2H2O(g)

i mol 0.10 0.050 0.10

c mol -0.038 -0.038 +0019 +0.038

e mol 0.062 0.012 00.019 0.057

Since the volume of the vessel is 1.0 L, the concentrations in molarity are:

[NO] = 0.062 M

[H2] = 0.012 M

[N2] = 0.019 M

[H2O] = 0.057 M

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2 years ago

The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc

jek_recluse [69]

Answer: $K_{sp}=1.25\times 10^{-14}$

$pK_{sp}=13.90$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of magnesium phosphate is given as:

$Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}$

When the solubility of $Mg_3(PO_4)_2$ is S moles/liter, then the solubility of $Mg^{2+}$ will be 3S moles\liter and solubility of $PO_4^{3-}$ will be 2S moles/liter.

Thus S = 0.173 g/L or $\frac{0.173g/L}{262.8g/mol}=0.00065mol/L$

$K_{sp}=(3S)^3\times (2S)^2$

$K_{sp}=108S^5$

$K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}$

$pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90$

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2 years ago

What percentage of radioactive substance remains after two half-lives

Ksju [112]

Answer:

After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

Explanation:

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2 years ago

How many moles of CaCl2 are contained in 0.448 L of a 0.85 M CaCl2 solution?

kati45 [8]

Answer:

0.3808

Explanation:

number of moles,n=Conc.XVol.

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3 years ago