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Ierofanga [76]
3 years ago
9

Fused quartz possesses an exceptionally low coefficient of linear expansion, 5.50 × 10 − 7 ( ∘ C ) − 1 . Suppose a bar of fused

quartz of length 3.45 m at 20.0 ∘ C is heated to 235 ∘ C . By how much, in millimeters, would the bar expand?
Physics
1 answer:
kozerog [31]3 years ago
5 0

To solve this problem we will use the concepts related to thermal expansion in a body for which the initial length, the coefficient of thermal expansion and the temperature change are related:

\Delta L = L0\alpha\Delta T

Where,

\Delta L = Change in Length

\alpha = Coefficient of linear expansion

\Delta T = Change in temperature

L_0 = Initial Length

Our values are:

L_0 = 3.45m

\alpha = 5.5*10^{-7} \°C^{-1}

\Delta T = 235-20 = 215\°C

Replacing we have,

\Delta L = (3.49) (5.5*10^{-7}) [(215)

\Delta L = 0.0004126m

\Delta L = 0.4126mm

Therefore the change in milimiters was 0.4126mm

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A bullet with a mass of 0.02 kg is fired horizontally into a block of wood hanging on a string. The bullet sricks in the wood an
djyliett [7]

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1/2 m u²+ 0 = 0+ (m+M) g h

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7 0
3 years ago
. A stationary mass explodes into two parts of mass 4 kg and 40 kg . If the K.E of larger mass is 100 J . The K.E of small mass
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10J

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3 years ago
Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103
son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

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\frac{1}{2}mv^2 =\frac{Gm^2}{2R}

Re-arrange to find v,

v= \sqrt{\frac{Gm}{R}}

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2r = 2*10^3m

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v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}

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