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Anna007 [38]
3 years ago
7

The weight of a liter of oil that has a specific gravity 0.83 is a) 3.0 N b) 8.1 N c)0.18N d) 18.0 N e) None of these

Engineering
1 answer:
zepelin [54]3 years ago
4 0

Answer:

Weight of oil will be 8.1 N

So option (b) is correct

Explanation:

We have given specific gravity of oil = 0.83

We know that specific gravity is given by specific\ grviy=\frac{density\ of\ oil}{density\ of\ water}

So 0.83=\frac{density\ of\ oil}{1000}

Density of oil 83kg/m^3

Volume is given as 1 liter = 10^{-3}m^3

We know that mass m=volume\times density=10^{-3}\times 83=0.83

Weight of oil is given by W=mg=0.83\times 9.81=8.1N

So option (b) is correct

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You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea
Reika [66]

Answer: 33.35 minutes

Explanation:

A(t) = A(o) *(.5)^[t/(t1/2)]....equ1

Where

A(t) = geiger count after time t = 100

A(o) = initial geiger count = 400

(t1/2) = the half life of decay

t = time between geiger count = 66.7 minutes

Sub into equ 1

100=400(.5)^[66.7/(t1/2)

Equ becomes

.25= (.5)^[66.7/(t1/2)]

Take log of both sides

Log 0.25 = [66.7/(t1/2)] * log 0.5

66.7/(t1/2) = 2

(t1/2) = (66.7/2 ) = 33.35 minutes

4 0
3 years ago
A ball slowly starts to roll downhill, but its speed increases as it rolls. How are the ball's speed and energy related? - Why d
netineya [11]

Answer:

the ball gains speed because of the force of the earth pulling on it and the kinetic energy coming ffrom the potental energy

Explanation:

7 0
4 years ago
19 million Joules of chemical energy are supplied to a boiler in a power plant. 5 x 106 Joules of energy are lost through unburn
Fiesta28 [93]

Answer:

67.89%

Explanation:

Energy Efficiency=\frac {U_{energy}}{T_{energy}}\times 100

Where U_{energy} is useful energy and T_{energy} is the total energy

The useful energy= (19-5-1.1) million= 12.9 million

The total energy= 19 million

Efficiency=\frac {12.9}{19}\times 100=67.89473684\approx 67.89

Therefore, the efficiency of the boiler is 67.89%

8 0
3 years ago
If the maximum allowable shear stress is 70 MPa, find the shaft diameter needed to transmit 40 kW when the shaft speed is 250 rp
victus00 [196]

Answer:

The diameter is 50mm

Explanation:

The answer is in two stages. At first the torque (or twisting moment) acting on the shaft and needed to transmit the power needs to be calculated. Then the diameter of the shaft can be obtained using another equation that involves the torque obtained above.

T=(P×60)/(2×pi×N)

T is the Torque

P is the the power to be transmitted by the shaft; 40kW or 40×10³W

pi=3.142

N is the speed of the shaft; 250rpm

T=(40×10³×60)/(2×3.142×250)

T=1527.689Nm

Diameter of a shaft can be obtained from the formula

T=(pi × SS ×d³)/16

Where

SS is the allowable shear stress; 70MPa or 70×10⁶Pa

d is the diameter of the shaft

Making d the subject of the formula

d= cubroot[(T×16)/(pi×SS)]

d=cubroot[(1527.689×16)/(3.142×70×10⁶)]

d=0.04808m or 48.1mm approx 50mm

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4 years ago
Which of the following have had a significant impact on the automotive industry?
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All of the above (hope that helps!)
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