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3 years ago

The weight of a liter of oil that has a specific gravity 0.83 is a) 3.0 N b) 8.1 N c)0.18N d) 18.0 N e) None of these

Engineering

1 answer:

zepelin [54]3 years ago

4 0

Answer:

Weight of oil will be 8.1 N

So option (b) is correct

Explanation:

We have given specific gravity of oil = 0.83

We know that specific gravity is given by $specific\ grviy=\frac{density\ of\ oil}{density\ of\ water}$

So $0.83=\frac{density\ of\ oil}{1000}$

Density of oil $83kg/m^3$

Volume is given as 1 liter = $10^{-3}m^3$

We know that mass $m=volume\times density=10^{-3}\times 83=0.83$

Weight of oil is given by $W=mg=0.83\times 9.81=8.1N$

So option (b) is correct

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3 years ago

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max2010maxim [7]

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