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saveliy_v [14]
3 years ago
9

What are the main factors for the high material removal rate in broaching operations?

Engineering
1 answer:
Umnica [9.8K]3 years ago
6 0

Answer:

Explanation:

Broaching:

  Broaching is a metal removal process or we can say that it is a machining process.Generally broach have three types teeth in which first one is called roughing teeth,second one semi finishing and third  one finishing teeth.By using these teeth metal remove so fast and that is why broaching is the high metal removal rate operation.

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What website is the bets for paper planes ?
poizon [28]

Answer:

https://www.origamiway.com/paper-airplane-instructions.shtml

Explanation:

This is a more personal preference, so at the end of the day it is what works best for you :D

Hope this helps!

3 0
4 years ago
6. At a construction site, cement, sand, and gravel are used to make concrete. The ratio of cement to sand to gravel is 1 to 2.4
S_A_V [24]

Answer:

Mass of cement used is 62.5 lb

Mass of gravel used is 225 lb

Explanation:

The ratio given here is cement to sand to gravel = 1 : 2.4 : 3.6

So, for 150 lb of sand

C : S : G = 1 : 2.4 : 3.6

\frac{C}{S}=\frac{1}{2.4}\\\Rightarrow C=S\frac{1}{2.4}\\\Rightarrow C=150\frac{1}{2.4}\\\Rightarrow C=62.5\ lb

Mass of cement used is 62.5 lb

\frac{S}{G}=\frac{2.4}{3.6}\\\Rightarrow G=S\frac{3.6}{2.4}\\\Rightarrow C=150\frac{3.6}{2.4}\\\Rightarrow C=225\ lb

Mass of gravel used is 225 lb

7 0
3 years ago
Which is an example of a subsystem and system relationship?
Zanzabum

The example of a subsystem and system relationship is option

A) mechanical toggle, Xbox controller

Explanation:

  • Controls and Controllers are known as the mechanical, electro-mechanical, or electronic devices which are used to  input signals to change the conditions or values which are in processes or access to buildings, operators, gated areas, etc.
  • When you press and hold the given Shift button, these buttons which are chosen becomes an alternate inputs.
  • Normally, there are three controllers(PID) which are used in any of the process industries inorder to maintain and control the required setpoint.
  • an example of a subsystem and system relationship is a mechanical toggle, Xbox controller
  • Controllers improve the steadiness and state of accuracy by decreasing the steady state error. When the steady state accuracy gets better, the stability also improves.
  • Controllers are also used to help in reducing the unwanted offsets which are produced by the system.

6 0
3 years ago
Independent auto lots usually have ____ finance rates than dealerships
wel

Independent auto lots usually have <u>higher</u> finance rates than dealerships

<u>Explanation:</u>

The finance rates that are charged by the dealers are lower than the finance charges that are charged by the independent auto. In case if you are getting financed through dealerships, you can also negotiate with them to charge finance rates and lower the charges of the finance.

But this negotiation and lowering of the finance rates is not possible with the independent auto lots and thus they charge higher rates compared to the dealerships.

8 0
3 years ago
The density of a liquid is to be determined by an old 1-cm-diameter cylindrical hydrometer whose division marks are completely w
vodka [1.7K]

Answer:

The density of the unknown liquid is 1.025 kg/m³ (considering the density of the water as 1.000 kg/m³)

Explanation:

The hydrometer works by the Archimedes principle. The cylinder floats in the liquid because the hydrostatic thrust is equal to the weight force. This means:

Tr-W=0N\\Tr=W\\\delta_{fl} \cdot Vol \cdot g =W_{hydr}

If we measure 2 fluids, the weight of the hydrometer is the same, so:

\delta_{fl1} \cdot Vol_1 \cdot g =W_{hydr}=\delta_{fl2} \cdot Vol_2 \cdot g\\\delta_{fl1} \cdot Vol_1 =\delta_{fl2} \cdot Vol_2\\\delta_{fl1} H_1 \pi R^2 =\delta_{fl2} H_2 \pi R^2\\\delta_{fl1}\frac{H_1}{H_2}=\delta_{fl2}

If the original watermark height is 12.3cm (H₁) and the mark for water has risen 0.3 cm above the unknown liquid–air interface, the height of the unknown liquid mark is 12cm (H₂). Therefore:

delta_{fl1}\frac{H_1}{H_2}=\delta_{fl2}\\1.000\frac{kg}{m^3} \frac{12.3cm}{12cm}=\delta_{fl2}=1.025\frac{kg}{m^3}

8 0
3 years ago
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