Question

Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded correctly.

Answer 1

This question is an incomplete question, here is a complete question.

Perform the following calculation. Report the answer using the proper number of significant figures.

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}=?$

Answer : The answer will be, $3.46J/g.K$

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

The given expression is,

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}$

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (0.0115)K}$

$\Rightarrow 3.4569J/g.K$

In the given expression, 1.012 has 4 significant figures, 0.025456 has 5 significant figures and 0.0115 has 3 significant figures. From this we conclude that 3 is the least significant figures in this problem. So, the answer should be in 3 significant figures.

Thus, the answer will be $3.46J/g.K$