What evidence of a chemical reaction might you see in the following cases?

Chemistry

2 answers:

DerKrebs [107]3 years ago

5 0

ALL OF THE ABOVE ARE CHEMICAL CHANGE WHICH IS IREVERSIBLE TO THE ORIGINAL STATE

telo118 [61]3 years ago

4 0

In bleaching a stain, you see that the stain fades, and doesn't come back, which indicates that it has undergone a change.

Buring a match, you would see the ashes, and that it cannot be it's original substance again.

In rusting of an iron nail, the nail cannot be unrusted easily, which indicates that it has been through a chemical reaction.

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What would happen to the following endothermic reaction that is in equilibrium if heat is added? N2O4 (g) Two arrows stacked on

Ber [7]

The reaction N2O4 (g) <--> 2NO2 (g) is endothermic, meaning that it consumes heat to move towards formation of the products.
According to Le Chatelier's Principle, therefore, if heat is added, more product (NO2) will be produced, and equilibrium would shift towards the right side. This is choice 3.

6 0

3 years ago

Read 2 more answers

What quantity is the same among atoms of the same element?

Vedmedyk [2.9K]

Answer:

Neutrons or Neutral atoms

Explanation:

Neutral atoms of each element contain an equal number of protons and electrons. The number of protons determines an element's atomic number and is used to distinguish one element from another.

8 0

3 years ago

Alkynes are reduced to trans alkenes by a process called dissolving metal reduction. The reaction uses sodium or lithium metal a

NISA [10]

Answer:

Explanation:

The movement of the electrons is illustrated in the picture attached to this answer. It is a four-step reaction mechanism.

First STEP: The first step involves the transfer of an electron from sodium to form a radical anion.

Second STEP: This radical anion then removes a proton/hydrogen from ammonia in a bid to neutralize itself (hence the hydrogen becomes bonded to the anion).

Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.

Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.

NOTE: The circled numbers denote each step while the mechanism on the left represents the use of any alkyl group (R and R') while the mechanism on the right assumes both alkyl groups are methyl. Hence, 2-butyne started the reaction and the final product was trans-2-butene.