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Alex
3 years ago
15

which cell structure is responsible for taking in and breaking down foreign particles and damaged organelles?

Physics
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

lysosomes

Explanation:

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At what height h above the ground does the projectile have a speed of 0.5v?
maw [93]

Answer:

h=\dfrac{3v^2}{8g}

Explanation:

It is given that,

Speed of the projectile is 0.5 v. Let h is the height above the ground. Using the first equation of motion to find it.

v=u+at

v=u-gt

Initial speed of the projectile is v and final speed is 0.5 v.

0.5v=v-gt

t=\dfrac{v}{2g}

g is the acceleration due to gravity

Let h is the height above the ground. Using the second equation of motion as :

h=vt-\dfrac{1}{2}gt^2

h=v\dfrac{v}{2g}-\dfrac{1}{2}g(\dfrac{v}{2g})^2

h=\dfrac{3v^2}{8g}

So, the height of the projectile above the ground is \dfrac{3v^2}{8g}. Hence, this is the required solution.

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3 years ago
Chemical substances in food that have specific functions in your body are called?
andreev551 [17]

Answer:

Chemical substances in food that have specific functions in your body are called Nutrients. Examples: proteins, fats, carbohydrates, vitamins, and minerals

Explanation:

These chemical substances keep our body healthy.

These chemical substances prevent the premature aging.

They help our body to fight against diseases.

They build the new tissues and cells for growth.

And in short, they help in the growth, development of our body.

4 0
3 years ago
You can see yourself in the mirror because?
jok3333 [9.3K]
Mirrors reflect light waves.
3 0
2 years ago
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Question 6 Multiple Choice Worth 4 points)
allsm [11]

is iron and aluminium is there

6 0
2 years ago
A piece of wire 29 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
skelet666 [1.2K]

Answer:

Explanation:

Total length of the wire is 29 m.

Let the length of one piece is d and of another piece is 29 - d.

Let d is used to make a square.

And 29 - d is used to make an equilateral triangle.

(a)

Area of square = d²

Area of equilateral triangle = √3(29 - d)²/4

Total area,

A = d^{2}+\frac{\sqrt3}{4}\left ( 29-d \right )^{2}

Differentiate both sides with respect to d.

\frac{dA}{dt}=2d- \frac{\sqrt3}{4}\times 2(29-d)

For maxima and minima, dA/dt = 0

d = 8.76 m

Differentiate again we get the

\frac{d^{2}A}{dt^{2}}= + ve

(a) So, the area is maximum when the side of square is 29 m

(b) so, the area is minimum when the side of square is 8.76 m

8 0
3 years ago
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