Answer:
Explanation:
In this case we will use the Bohr Atomic model.
We have that: 
We can calculate the centripetal force using the coulomb formula that states:
Where K=
and r is the distance.
Now we can say:
The mass of the electron is = 
Kg
The charge magnitud of an electron and proton are= 
Substituting what we have:
![[tex]a=\frac{9*10^{9}*(1.6*10^{-19} )*(2(1.6*10^{-19} ))}{9.1*10^{-31}*(2.99*10^{-11})^2 }](https://tex.z-dn.net/?f=%5Btex%5Da%3D%5Cfrac%7B9%2A10%5E%7B9%7D%2A%281.6%2A10%5E%7B-19%7D%20%29%2A%282%281.6%2A10%5E%7B-19%7D%20%29%29%7D%7B9.1%2A10%5E%7B-31%7D%2A%282.99%2A10%5E%7B-11%7D%29%5E2%20%7D)
[/tex]
so:
Answer:
3 kg
Explanation:
Momentum before = momentum after
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
After jumping on the skateboard, the student and the skateboard have the same velocity, so v₁ = v₂.
m₁u₁ + m₂u₂ = (m₁ + m₂) v
(47.4 kg) (4.2 m/s) + m (0 m/s) = (47.4 kg + m) (3.95 m/s)
m = 3 kg
Hence, the horizontal velocity of the rover is 1.73 m/s
Answer:
a) T = (2,375 ± 0.008) s
, b) When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Explanation:
a) The period of a simple pendulum is
T = 2π √ L / g
Let's calculate
T = 2π √1.40 / 9.8
T = 2.3748 s
The uncertainty of the period is
ΔT = dT / dL ΔL
ΔT = 2π ½ √g/L 1/g ΔL
ΔT = π/g √g/L ΔL
ΔT = π/9.8 √9.8/1.4 0.01
ΔT = 0.008 s
The result for the period is
T = (2,375 ± 0.008) s
b) the experimental measure was T = 2.39 s ± 0.01 s
The theoretical value is comprised in a range of [2,367, 2,387] when we approximate this measure according to the significant figures the interval remains [2,37, 2,39].
When comparing this interval with the experimental value we see that it is within the possible theoretical values.
