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iVinArrow [24]
3 years ago
12

Examine the models shown above.where is potential energy the greatest

Chemistry
1 answer:
Lisa [10]3 years ago
7 0

Answer:

A

Explanation:

Because it is the greatest

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Why does nuclear charge increase as you go left to right across a period
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 The atomic number increases moving left to right across a period and subsequently so does the effective nuclear charge. Therefore, moving left to right across a period the nucleus has a greater pull on the outer electrons and the atomic radii decreases.

7 0
3 years ago
Which of these compounds is a proton acceptor ?
Vikki [24]

Answer:

Sodium Hydroxide

Please mark me as brainlest because I have help you pleaseeeee.

Explanation:

Sodium hydroxide is a common proton acceptor also known as lye. It is the active ingredient in oven cleaners and drain cleaners because it can react with fats to produce compounds that dissolve in water. It is also used in many school laboratories to demonstrate acid-base reactions.

5 0
3 years ago
Atoms of metallic elements tend to
melomori [17]

Answer:

D

Explanation:

One of the properties of metals is their abilities to form a stable compounds by losing electron(s). Metals form positive ions (cations) when they lose electron(s).

6 0
3 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
Tin reacts with Fluorine to form two different compounds, A and B. Compounds A contains 77.0 g tin for each 24.6 g of fluorine.
Ratling [72]
A contains 38.5 g of tin for each 12.3 g of fluorine: 
<span>mole ratio: </span>
<span>(38.5 g)/(118.71 g/mol):(12.3 g)/(18.998 g/mol) = 0.324:0.647 = 1:2 ⇒ SnF₂ </span>

<span>B contains 56.5 g of tin for each 36.2 g of fluorine: </span>
<span>mole ratio: </span>
<span>(56.5 g)/(118.71 g/mol):(36.2 g)/(18.998 g/mol) = 0.476:1.905 = 1:4 ⇒ SnF₄

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3 0
3 years ago
Read 2 more answers
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