Answer:
Explanation:
We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 261.34 233.39
Ba(NO₃)₂ + Na₂SO₄ ⟶ BaSO₄ + 2NaNO₃
m/g: 75.00
1. Moles of Ba(NO₃)₂
2. Moles of BaSO₄
The molar ratio is (1 mol BaSO₄/1 mol Ba(NO₃)₂
3. Mass of BaSO₄
Answer:
yo that's too long you should try and my it shorter
Ultraviolet–visible spectroscopy<span> or ultraviolet-visible spectrophotometry </span><span>refers to absorption </span>spectroscopy or reflectance spectroscopy<span> in the ultraviolet-visible spectral region. This means it uses light in the visible and adjacent (near-</span>UV<span> and near-infrared [NIR]) ranges.
I hope this helps!</span>
For this we have to consider the reactive series of metals in which metals are arranged according to their reactivity order.
Oxidation of a metal can be defined as ability to lose electrons to become positively charged metal and a metal will lose its electrons by reacting with a metal that is having low chemical reactivity as a higher reactive metal can lose its electrons to a low reactive metal. So here a metal should be one that is more reactive than tin so that it can lose its electrons to tin to become positively charged and less reactive than iron so that it will not give its electrons to iron to become positively charged. If we look into reactive series of metal than we will find that nickel is the example of a metal that is more reactive than tin and less reactive than iron.