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attashe74 [19]
3 years ago
9

A force of 720 Newton stretches a spring 4 meters. A mass of 45 Kilograms is attached to the spring and is initially released fr

om the equilibrium position with an upward velocity of 6 meters per second. Find an equation of the motion.

Physics
1 answer:
poizon [28]3 years ago
5 0

Answer:

x(t) = -3sin2t

Explanation:

Given that

Spring force of, W = 720 N

Extension of the spring, s = 4 m

Attached mass to the spring, m = 45 kg

Velocity of, v = 6 m/s

The proper calculation is attached via the image below.

Final solution is x(t) = -3.sin2t

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A plane lands on a runway with a speed of 115 m/s, moving east, and it slows to a stop in 13.0 s. What is the magnitude (in m/s2
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<em>Given: v = 115 m/s, t = 13.0 s</em>

<em>Substituting these values into equation 1</em>

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The thermal energy that is generated due to friction is 344J.

<h3>What is the thermal energy?</h3>

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Learn more about thermal energy due to friction:brainly.com/question/7207509

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