Missing question:
"Determine (a) the astronaut’s orbital speed v and (b) the period of the orbit"
Solution
part a) The center of the orbit of the third astronaut is located at the center of the moon. This means that the radius of the orbit is the sum of the Moon's radius r0 and the altitude (

) of the orbit:

This is a circular motion, where the centripetal acceleration is equal to the gravitational acceleration g at this altitude. The problem says that at this altitude,

. So we can write

where

is the centripetal acceleration and v is the speed of the astronaut. Re-arranging it we can find v:

part b) The orbit has a circumference of

, and the astronaut is covering it at a speed equal to v. Therefore, the period of the orbit is

So, the period of the orbit is 2.45 hours.
Answer:
The power dissipated in either one of the parallel resistors is 2 V
Explanation:
Given;
two parallel resistors, R₁ and R₂ = 2 ohms
The total resistance of the Two resistors of 2 ohms connected in parallel is;

when connected to another resistor of 1 ohm in series, the total resistance becomes;
Rt = R₁ + R₂
Rt = 1 + 1 = 2 ohms
Current in the circuit, I = voltage / total resistance
= 2 /2 = 1 A
the overall circuit has been resolved to series connection, and current flow in series circuit is constant.
Power = I²R
Thus, power dissipated in either one of the parallel 2 ohms resistors is;
Power = I²R = (1)² x 2 = 2 V
Answer:
Although there are only 118 elements that have been discovered and entered in the Periodic Table, there is an almost infinite multiplicity of things, materials, resources and other objects in the universe.
This is so because each of these elements can be combined with the others, varying its proportion and the inclusion of different elements, forming different things according to the proportion in which each element has been used.
Answer:
The pendulum with the greatest frequency is one with short length.
Explanation:
A simple pendulum is a device which consists of mass m hanging from the string of length L attached to the some point.When displaced and released its swings back and forth with periodic motion.
The frequency of simple pendulum is given by
f = 
where T is the time period.
f =1/2π√g/l
where , l is the length of pendulum
g is acceleration due to gravity.
The frequency of simple pendulum is defined as how much time or the distance covered by the bob in one second
From the given equation we can find that the frequency of the simple pendulum is<em> inversely proportional</em> to square root of length.Hence the frequency will be maximum if the length of the bob is short.