Answer:
13.33 seconds
Explanation:
At maximum height, the equation of motion becomes:
<em> v = u + at</em>
Since the object was thrown vertically, the initial velocity (u) is zero and the acceleration (a) becomes the acceleration due to gravity (10 m/s2). The equation becomes:
<em>v = at</em>
<em>v = 480 k</em>m/hr = 133.333 m/s
10t = 133.333
t = 133.333/10
t = 13.33 seconds.
<em>The time for the ball thrown vertically with a velocity of 480 km/hr to reach the maximum height is </em><em>13.33 seconds</em><em>.</em>
Answer:
zero
Explanation:
In this system, only conservative forces act. Therefore, the mechanical energy, that is, the sum of the kinetic energy and the potential energy, remains constant. When the mass is at its maximum displacement from equilibrium, its potential energy is maximum, therefore, its kinetic energy is minimal, that is to say, that its instantaneous velocity at that point is zero.
The displacement of the particle in the time interval 5 seconds to 8 seconds will be 1.5 meters.
Displacement is a vector quantity; meaning it has both magnitude and direction; magnitude being the distance between the interval at 5 seconds and position at 8 seconds, while the direction is from position at 5 second to position at 8 second. This is irrespective of the route followed during the time interval.
