<u>Answer:</u> The partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg
<u>Explanation:</u>
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
The equation given by Henry's law is:
......(1)
where,
= solubility of carbon dioxide in water = 0.161 g/100 mL
= Henry's constant = ?
= partial pressure of carbon dioxide = 760 mmHg
Putting values in equation 1, we get:
Now, calculating the pressure of carbon dioxide using equation 1, we get:
= solubility of carbon dioxide in water = 0.886 g/100 mL
= Henry's constant = 4720.5 g.mmHg/100 mL
= partial pressure of carbon dioxide = ?
Putting values in equation 1, we get:
Hence, the partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg
Answer:
Mass = 0.697 g
Explanation:
Given data:
Volume of hydrogen = 1.36 L
Mass of ammonia produced = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
First of all we will calculate the number of moles of hydrogen:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K
1.36 atm.L = n × 22.43 atm.L/mol
n = 1.36 atm.L / 22.43 atm.L/mol
n = 0.061 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
0.061 : 2/3×0.061 = 0.041
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.041 mol × 17 g/mol
Mass = 0.697 g
Atoms of oxygen are electronegative and attract the shared electrons in their covalent bonds.
The answer is burning paper
