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KIM [24]
3 years ago
8

A 2.0 kg box is placed on an inclined plane that forms an angle of 21 ° with the horizontal

Physics
1 answer:
Dmitrij [34]3 years ago
5 0

Answer:

.-2.0

Explanation:

as at 80 friction it's a 360?

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Find the 24th term of the arithmetic sequence 11, 14, 17, … . Express the 24 terms of the series of this sequence using sigma no
Anna71 [15]

Answer:

The 24th term is 80 and the sum of 24 terms is 1092.

Explanation:

Given that,

The arithmetic series is

11,14,17,........24

First term a = 11

Difference d = 14-11=3

We need to calculate the 24th term of the arithmetic sequence

Using formula of number of terms

t_{n}=a+(n-1)d

Put the value into the formula

t_{24}=11+(24-1)\times3

t_{24}=80

t_{24}=u_{24}=80

We need to calculate the sum of the first 24 terms of the series

Using formula of sum,

S_{n}=\dfrac{n}{2}(a+u_{24})

Put the value into the formula

S_{n}=\dfrac{24}{2}\times(11+80)

S_{n}=1092

Hence, The 24th term is 80 and the sum of 24 terms is 1092.

5 0
4 years ago
Consider the following four objects: a hoop, a flat disk, a solid sphere, and a hollow sphere. Each of the objects has mass M an
Mumz [18]

Answer:

The hoop

Explanation:

We need to define the moment of inertia of the different objects, that is,

DISK:

I_{disk} = \frac{1}{2} mR^2

HOOP:

I_{hoop} = mR^2

SOLID SPHERE:

I_{ss} = \frac{2}{5}mR^2

HOLLOW SPHERE

I_{hs} = \frac{2}{3}mR^2

If we have the same acceleration for a Torque applied, then

mR^2>\frac{2}{3}mR^2>\frac{1}{2} mR^2>\frac{2}{5}mR^2

I_{hoop}>I_{hs} >I_{disk}>I_{ss}

The greatest momement of inertia is for the hoop, therefore will require the largest torque to give the same acceleration

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3 years ago
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<span>150 kPa
While Titan is Saturns largest moon, it only has a mass of 0.0225 Earths
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What will angle r do?
timama [110]

Answer:

Increase

Explanation:

because it's increasing up.

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4 years ago
Cell are the ------- living part of an organism
lana66690 [7]

Answer:

3 smallest

Explanation:

3 0
3 years ago
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