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3 years ago

The pressure and absolute temperature of an ideal gas are both tripled, the volume is __________. not changed

Physics

1 answer:

ankoles [38]3 years ago

3 0

Answer:

Not Changed

Explanation:

To know what happened with the volume you need to know the Ideal gas Law

$\frac{P_{1}V_{1}}{T1} =\frac{P_{2}V_{2} }{T2}$

This law is a combination of the other four laws: Boyles's, Charles's, Avogadro's, and Guy-Lussac's.

The initial state is represented by P1, V1, T1 and the final by P2, V2, T2.

In this case:

$T_{2} =3T_{1} \\P_{2} =3P_{1}$

Replacing on the equation

$\frac{P_{1}V_{1}}{T1} =\frac{3P_{1}V_{2}}{3T_{1} }$

If we clear from the equation V2

$\frac{P_{1}V_{1}3T_{1}}{T_{1} 3P_{1}} ={V_{2}}$

Then cancel both P1 and T1

$\frac{3V_{1}}{3} =V_{2}$

You will found that

$V_{1} =V_{2}$

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A parallel-plate vacuum capacitor has 8.38 J of energy stored in it. The separation between the plates is 2.30 mm. If the separa

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Answer:

Explanation:

plate separation = 2.3 x 10⁻³ m

capacity C₁ = ε A / d

= ε A / 2.3 x 10⁻³

C₂ = ε A / 1.15 x 10⁻³

$\frac{C_2}{C_1}$ = $\frac{2.3}{1.15}$

a ) when charge remains constant

energy = $\frac{q^2}{2C}$

q is charge and C is capacity

energy stored initially E₁= $\frac{q^2}{2C_1}$

energy stored finally E₂ = $\frac{q^2}{2C_2}$

$\frac{E_1}{E_2} = \frac{C_2}{C_1}$ = $\frac{2.3}{1.15}$

$E_2$ = $\frac{1.15}{2.3 } \times E_1$

= $\frac{1.15}{2.3 } \times 8.38$

= 4.19 J

b )

In this case potential diff remains constant

energy of capacitor = 1/2 C V²

energy is proportional to capacity as V is constant .

$\frac{E_2}{E_1} = \frac{C_2}{C_1}$

$\frac{E_2}{8.38} = \frac{2.3}{1.15}$

$E_2$ = 16.76 .

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Answer:

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Explanation:

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Every few hundred years most of the planets line up on the same side of the Sun.(Figure 1)Calculate the total force on the Earth

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Answer: $3.7 \times 10^{-4} N$

Explanation:

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$F = G\frac{Mm}{r^2}$

Where M and m are the masses of the object, r is the distance between the masses and G = 6.67× 10⁻¹¹ m³kg⁻¹ s⁻² is the gravitational constant.

We have to calculate the net force on Earth due to Venus, Jupiter and Saturn when they are in one line. It means when they are the closest distance.

$F_{net] = G\frac{M_eM_v}{r_v^2}+G\frac{M_eM_j}{r_j^2}+G\frac{M_eM_s}{r_s^2}$

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where 1 AU = 1.5 × 10¹¹ m

Inserting the values:

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