The magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.
Impulse:
The effect of applied force acting for a very small interval of time is known as Impulse.
Given data:
The initial magnitude of the force on Ball A is, F = 50 N.
The time interval for the applied force on Ball A is, t = 1.25 s.
And the impulse at initial on ball A is, I = 62.5 N-s.
Now, if force on ball A doubles, which means new magnitude of force is,
F' = 2F
F' = 2 × 50
F' = 100 N
For same time interval, the new impulse on Ball A is given as,
I' = F' × t
Solving as,
I' = 100 × 1.25
I' = 125 N-s
Taking the ratio of both the impulses as,
I' / I = 125/62.5
I' = 2 I
Thus, we can conclude that the magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.
Learn more about the impulse here:
brainly.com/question/904448
