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The hybridization of the C atom in CH₂Br₂ is sp3
When bonding, the orbitals "s" and "p" from C atoms interact to form hybridized orbitals. If the C atom has 4 sigma bonds, as is the case in CH₂Br₂, there are 4 hybridized orbitals required, so 1 "s" orbital and 3 "p" orbitals hybridize to form an sp3 hybrid orbital. This orbital has tetrahedral geometry and the bond angle is 109,5 °.
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Solid -> gas will need the increase in kinetic energy
To answer this question, we must first look at the
reactivity series table. From the table, we can see that those which are
located above are the most reactive while those below are less reactive. Which
means that elements cannot replace those elements which are above them.
From the series, platinum is below lead, hence there will
be no reaction.
Answer:
No reaction
Explanation:
Metals and non-metals can be identified either by their position in the periodic table or by their properties.
he metal elements are found on the left hand side of the periodic table, and the non-metal elements are found on the right. You can imagine a zig-zag line, starting at B-Al-Si, separating metals from non-metals.