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Olin [163]
3 years ago
15

The temperature within a thin plate with thermal conductivity of 10 W/m/K depends on position as given by the following expressi

on: TT=(100 K)????????−xx2/????????xx 2cos�yy/????????yy�+300 K Where, Lx = 1 m, and Ly = 2 m. At the point (0.4 m, 1 m), find: a. The magnitude of the heat flux b. The direction of the heat flux

Physics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

Heat flux = (598.3î + 204.3j) W/m²

a) Magnitude of the heat flux = 632.22 W/m²

b) Direction of the heat flux = 18.85°

Explanation:

- The correct question is the first image attached to this solution.

- The solution to this question is contained on the second and third images attached to this solution respectively.

Hope this Helps!!!

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user100 [1]

Answer:

2 i think

Explanation:

3 0
4 years ago
In Part 6.2.2, you will determine the wavelength of the laser by shining the laser beam on a "diffraction grating", a set of reg
harkovskaia [24]

Answer:

λ = 2042 nm

Explanation:

given data

screen distance d = 11 m

spot s = 4.5 cm = 4.5 ×10^{-2} m

separation L = 0.5 mm = 0.5 ×10^{-3} m

to find out

what is λ

solution

we will find first angle between first max and central bright

that is tan θ = s/d

tan θ = 4.5 ×10^{-2}  / 11

θ = 0.234

and we know diffraction grating for max

L sinθ  = mλ

here we know m = 1  so put all value and find λ

L sinθ  = mλ

0.5 ×10^{-3}  sin(0.234)  = 1 λ

λ = 2042.02 ×10^{-9}  m

λ = 2042 nm

3 0
4 years ago
a rural mail carrier leaves the post office and drives 22.0 km in a Northely direction. then drives in a 60° south of east direc
Scrat [10]

Answer:

<em>Good Luck!</em>

<em> 5 Stars</em>

<em />

Explanation:

7 0
3 years ago
How much work do you do when you lift a 100 N child 0.5 m?
Papessa [141]

Answer:

<h2>50 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 100 × 0.5

We have the final answer as

<h3>50 J</h3>

Hope this helps you

8 0
3 years ago
A 2kg block is sitting on a hinged ramp such that you can increase the angle of the incline. The coefficient of static friction
MariettaO [177]

Answer:

θ = 33.8

a = 3.42 m/s²

Explanation:

given data

mass m = 2 kg  

coefficient of static friction μs = 0.67

coefficient of kinetic friction μk = 0.25

solution

when block start slide

N = mg cosθ    .............1

fs = mg sinθ   ...............2

now we divide equation 2 by equation 1 we get

\frsc{fs}{N} = \frac{sin \theta }{cos \theta }

\frac{\mu s N }{N}  = tanθ

put here value we get

tan θ = 0.67

θ = 33.8

and

when block will slide  then we apply newton 2nd law

mg sinθ - fk = ma    ...............3

here fk = μk N = μk mg cosθ

so from equation 3 we get

mg sinθ -  μk mg cosθ = ma

so a will be

a = (sinθ - μk cosθ)g

put here value and we get

a = (sin33.8 - 0.25 cos33.8) 9.8

a = 3.42 m/s²

7 0
3 years ago
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