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Anastasy [175]
3 years ago
11

If light is used to promote the electron, what are the selection rules for the initial and final spin and orbital angular moment

um? Explain clearly.
Physics
1 answer:
loris [4]3 years ago
8 0

Answer:

(1)\Delta S=0

(2)\Delta L=0, +1,-1 but J=0 to J=0 transition not allowed.

Explanation:

Atoms can be described by the quantum number n, spin quantum number S, angular momentum quantum number L, and total angular momentum quantum number J. Based on approximation Russel- Saunders electron coupling, the atomic term symbol can be written as L_{J} ^{2S+1}.

The conditions or selection rule to promoting the electron are discussed below:

(1) The total spin should not change that is \Delta S=0.

(2) The total angular momentum change should be, \Delta L=0, +1,-1 but J=0 to J=0 transition not allowed.

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The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal
Anon25 [30]

Answer:

M= 0.4 Am^2

Explanation:

From the question we are told that:

Number of turns  N=5N=5

Conductor each with side length L=0.2m

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Magnetic field  B=50.0T

Generally the equation for the total magnetic moment  M is mathematically given by

M = current * area

M= I * A

M = 2 * (5* 0.2*0.2)  

M = 2 * 0.2

M= 0.4 Am^2

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3 years ago
For your final exam in electronics, you’re asked to build an LC circuit that oscillates at 10 kHz. In addition, the maximum curr
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Answer:

 L= 2 mH

C=1.26\times 10^{-7}\ F            

Explanation:

Given that

Frequency , f= 10 kHz

Maximum current ,I = 0.1 A

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The maximum energy stored in the inductor is given as follows

E=\dfrac{1}{2}LI^2

Where ,L= Inductance

I=Current

E=Energy

Now by putting the values in the above equation

10^{-5}=\dfrac{1}{2}\times L\times 0.1^2

L=\dfrac{2\times 10^{-5}}{0.1^2}\ H

L=0.002 H

L= 2 mH

We know that frequency f is given as

2\pi f=\dfrac{1}{\sqrt{LC}}

C=Capacitance  , f=frequency ,L=Inductance

Now by putting the values

2\pi \times 10\times 10^3=\dfrac{1}{\sqrt{0.002\times C} }

62831.85=\dfrac{1}{\sqrt{0.002\times C}}

\sqrt{0.002\times C=\dfrac{1}{62831.85}

0.002\times C=0.0000159^2

C=\dfrac{0.0000159^2}{0.002}\ F

C=1.26\times 10^{-7}\ F

Therefore the inductance and capacitance will be 2 mH and 1.26 x 10⁻⁷ F respectively.

6 0
3 years ago
Why do conductors transfer heat faster than insulators?
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Answer:

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Heat transfer by convection happens through the air, and there are millions of minuscule air spaces between the fibers. Heat transfer by radiation is also slow since one fiber must radiate its heat to another.

When we give heat then kinetic energy is increase and this heat is transferred from hot metal to cold metal through this free electrons. As in insulator the free electrons are negligible so that the heat is not transferred from hot junction to cold junction due to absence of this free electrons.

Explanation:

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Answer:

No, it is not attracted.

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