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Kisachek [45]
3 years ago
11

Which electromagnetic wave types have frequencies higher than visible light?

Physics
2 answers:
IgorLugansk [536]3 years ago
3 0

Answer:

The ones that we call 'ultraviolet', 'X-rays', and 'gamma rays' all have

higher frequency (shorter wavelength) than visible light.

Explanation:

Sindrei [870]3 years ago
3 0

Answer:

The other person was right. The answer is ultraviolet radiation.

Explanation:

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A 200g piece of iron is heated at 100C. It is than dropped into water to bring its temperature down to 22C. What is the amount o
gizmo_the_mogwai [7]

Answer:

6926.4J

Explanation:

Given parameters:

Mass of iron  = 200g

Initial temperature  = 100°C

Final temperature  = 22°C

Unknown:

Amount of heat transferred to the water  = ?

Solution:

The quantity of heat transferred to the water is a function of mass and temperature of the iron;

 H  = m c Ф

m is the mass of the iron

Ф is the change in temperature

C is the specific heat capacity of iron = 0.444 J/g°C

Now;

 insert the parameters and solve;

      H  = 200 x 0.444 x (100-22)

      H = 6926.4J

8 0
3 years ago
1. Compare the speed that light waves travel in air to the speed that sound waves travel in the air. How many times faster do li
Vladimir79 [104]

Answer:

895522 times faster.

Explanation:

From the question given above, the following data were obtained:

Speed of sound in air (v) = 335 m/s

Speed of light in air (c) = 3×10⁸ m/s

How many times faster =.?

To obtain how many times faster light travels in air than sound, do the following

c : v => 3×10⁸ : 335

c/v = 3×10⁸ / 335

c/v = 895522

Cross multiply

c = 895522 × v

From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.

Thus, light travels 895522 times faster than sound in air.

6 0
2 years ago
A temperature of 273 K is the temperature at which water
xz_007 [3.2K]
<span>273 K is the freezing point of water and it is equal to 0 degrees Celcius ,In this change ,heat is released so as to gain the suitable temperature for freezing.273 K is just the Celsius scale but with being 0 but the same scale ,this number was arrived at because temperature comes from the motion of a substance's particles.</span>
5 0
3 years ago
A constant tone is being applied to a speaker. The voltage across the speaker is 5 volts. The voltage across the speaker is incr
lubasha [3.4K]

Answer:

decibel gain is 10 db

Explanation:

given data

voltage v1 =  5 volts

voltage v2 = 15 volts

to find out

decibel gain

solution

we have given that 5 volt voltage that is increase to 15 volts

so

we know here decibel gain formula that is

decibel gain = 20 log(v2/v1)   ....................1

put here value of v1 and v2  in equation 1

decibel gain = 20 log(15/5)

decibel gain = 20 log3

decibel gain = 20 × 0.4771

decibel gain = 9.54 db = approx 10 db

so decibel gain is 10 db

5 0
3 years ago
Read 2 more answers
What property of a solid would be most important if you were calculating how much paint was required to cover it?
Nadusha1986 [10]
Define shape and volume

Because: The area of the shape is how much paint would cover the object
6 0
3 years ago
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