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3 years ago

Which electromagnetic wave types have frequencies higher than visible light?

Physics

2 answers:

IgorLugansk [536]3 years ago

3 0

Answer:

The ones that we call 'ultraviolet', 'X-rays', and 'gamma rays' all have

higher frequency (shorter wavelength) than visible light.

Explanation:

Sindrei [870]3 years ago

3 0

Answer:

The other person was right. The answer is ultraviolet radiation.

Explanation:

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An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o

Alekssandra [29.7K]

Answer:

$0.53m/s^2$

Explanation:

We are given that

Mass of wire=m=3.6 g= $3.6\times 10^{-3} kg$

1 kg=1000 g

Length of wire=l=1.6 m

Mass of object=m'=3 kg

Time,t=60.1 ms= $60.1\times 10^{-3} s$

$1 ms=10^{-3} s$

Speed,v= $\frac{distance}{time}=\frac{1.6}{60.1\times 10^{-3}}=26.62 m/s$

$g=\frac{v^2m}{m'l}$

Using the formula

$g=\frac{(26.62)^2\times 3.6\times 10^{-3}}{3\times 1.6}=0.53m/s^2$

8 0

4 years ago

The Earth’s diameter is about 8,000 miles; our Moon’s diameter is about 2,000 miles; how

Vitek1552 [10]

Three moons can fit inside the volume of the sun.

The moon is a non luminous body found in the space. It could cause a solar eclipse when it comes between the sun and the earth.

Since the Earth’s diameter is about 8,000 miles and the Moon’s diameter is about 2,000 miles, to obtain the number of moons that could fit inside the sun we have;

8,000 miles/ 2,000 miles = 3

Hence, three moons can fit inside the volume of the sun.

Learn more about the moon:brainly.com/question/13538936

#SPJ1

6 0

2 years ago

1. A negatively charged rod is moved near the top of a positively charged electroscope. What

Xelga [282]

Answer:

A) Moves closer together

7 0

3 years ago

Which microbes can be Eukaryotic? A. bacteria B. virus C. protists D. fungi

MissTica

Hey there,

Question : Which microbes can be Eukaryotic?

Answer : A, Bacteria

Hope this helps :D

<em>~Top♥</em>

3 0

4 years ago

Read 2 more answers

The water level in a tank is 20 m above the ground. a hose is connected to the bottom of the tank, and the nozzle at the end of

Damm [24]

Answer:

P_(pump) = 98,000 Pa

Explanation:

We are given;

h2 = 30m

h1 = 20m

Density; ρ = 1000 kg/m³

First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

Thus, it can be expressed as;

P_(tank)+ P_(pump) = P_(nozzle)

Now, the pressure would be given by;

P = ρgh

So,

ρgh_1 + P_(pump) = ρgh_2

Thus,

P_(pump) = ρg(h_2 - h_1)

Plugging in the relevant values to obtain;

P_(pump) = 1000•9.8(30 - 20)

P_(pump) = 98,000 Pa

5 0

3 years ago