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vova2212 [387]
3 years ago
13

MnS+HCl H 2 S+MnCl 2 Which set of coefficients would balance the equation?

Physics
1 answer:
rewona [7]3 years ago
3 0

Answer:

1,2,1,1

Explanation:

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Small, slowly moving spherical particles experience a drag force given by Stokes' law: Fd = 6πηrv where r is the radius of the p
Dominik [7]

Answer:

Explanation:

At the time of a body achieving terminal velocity, the drag force becomes equal to the weight of the body less the buoyant force by the surrounding medium which can be represented by the following equation

\frac{4\pi\times r^3(d-\rho)}{3} =6\pi\times n\times r\times v

Where r is radius of the body , d is density of the material of the body σ is density of the medium and n is coefficient of viscosity of the medium and v is terminal velocity.

Simplifying

v = \frac{2\times r^2(d-\rho)}{9\times n}

Assuming the value of density of air as 1.225 kg/m³ and putting other given values in the formula we get

v = [tex]\frac{2\times (1.2\times10^{-5})^2(2182-1.225)}{9\times 1.8\times10^{-5}}[/tex]

v = 387 x 10⁻⁵ m/s

Terminal velocity = 387 x 10⁻⁵ m/s

Time taken to fall a distance of 100 m

= \frac{100}{387\times10^{-5}}

= 2.6 x 10⁴ s.

5 0
3 years ago
2. How can people know that they've learned?
photoshop1234 [79]
Answer: People know that they jap e learned by their mistakes or by someone ya being them something
4 0
3 years ago
_____ has the potential to superimpose digital data over real photos so that GPS maps can be combined with real pictures of stor
IRISSAK [1]

<u>Augmented reality</u> has the potential to superimpose digital data over real photos so that GPS maps can be combined with real pictures of stores and streets to help people locate their position.

<u>Explanation:</u>

An engaging perception of an original globe atmosphere, where by computer-generated perceptual knowledge the transformation of real-world entities take place and also by multiple sensory modalities, involving somatosensory, visual, auditory, haptic and olfactory forms, thus known as augmented reality.

AR app uses GPS and camera from a smartphone to deploy an augmented reality-enabled GPS navigation system. As in the web, AR tool termed as Real View Navigation is accessible to all Android and iOS clients. Google is brought its first virtual reality walking directions, now recognized as Live Experience on Google Maps.

4 0
3 years ago
if gas in a sealed container has a pressure of 50kpa at 300k what will the pressure be if the tempature rises to 360k
Zarrin [17]
The pressure law states that pressure is directly proportional to temperature.
p=kt where p is pressure, k is a constant, and t is temperature.

p=kt -- substitute
50000=k*300000
k=1/6
p=1/6*360000
p=60000 -- in pa not kpa

The pressure is 60kpa
3 0
3 years ago
Question 2
Delvig [45]

Answer:

Approximately 73\; {\rm N}, assuming that the acceleration of this ball is constant during the descent.

Explanation:

Assume that the acceleration of this ball, a, is constant during the entire descent.

Let x denote the displacement of this ball and let t denote the duration of the descent. The SUVAT equation x = (1/2)\, a\, t^{2} would apply.

Rearrange this equation to find an expression for the acceleration, a, of this ball:

\begin{aligned} a &= \frac{2\, x}{t^{2}}\end{aligned}.

Note that x = 11\; {\rm m} and t = 1.5\; {\rm s} in this question. Thus:

\begin{aligned} a &= \frac{2\, x}{t^{2}} \\ &= \frac{2 \times 11\; {\rm m}}{(1.5\; {\rm s})^{2}} \\ &\approx 9.78\; {\rm m \cdot s^{-2}}\end{aligned}.

Let m denote the mass of this ball. By Newton's Second Law of Motion, if the acceleration of this ball is a, the net external force on this ball would be m\, a.

Since m = 7.5\; {\rm kg} and a \approx 9.78\; {\rm m\cdot s^{-2}}, the net external force on this ball would be:

\begin{aligned} (\text{net force}) &= m\, a \\ &\approx 7.5\; {\rm kg} \times 9.78\; {\rm m\cdot s^{-2}} \\ &\approx 73\; {\rm kg \cdot m \cdot s^{-2} \\ &= 73\; {\rm N} && (1\; {\rm N} = 1\; {\rm kg \cdot m\cdot s^{-2}}) \end{aligned}.

4 0
2 years ago
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