Answer:
17g
Explanation:
4NH3 (g) + 502 (g) –> 4NO (g) + 6H20 (g)
Mass of O2 mole = 32g
Therefore 5O2 = 160g
Mass of NH3 mole = 17g
Therefore 4NH3 = 17 x 4 =68g
Required amount of NH3 = 68 x 40/160 = 17g
Answer:
See explanation
Explanation:
We have to remember that the formula of <u>sulfur dioxide</u> is . So, the "S" atom is the central one and the "O" atoms are in the left and right of S. Additionally, "S" and "O" atom has <u>6 valence electrons each</u>. With this in mind, we can start with a structure in which the left oxygen has 2 lone pairs and a double bond, the S atom can have a double bond a single bond and a lone pair and the right oxygen with 3 lone pairs with a single bond <u>(structure A)</u>. Now, if we move the negative charge in the right (resonance) to the middle and the double bond to the left oxygen we will obtain <u>structure B</u>. Finally, we can move the negative charge in the left to the middle and we will obtain structure C. (See figure 1).
Answer: 0.422 M⁻¹s⁻¹
Explanation: <u>Reaction</u> <u>Rate</u> is the speed of decomposition of the reactant(s) per unit of time.
A <u>Rate</u> <u>Law</u> relates concentration of reactants, rate reaction and rate constant:
where
[A] and [B] are reactants concentration
x and y are reaction order, not related to the stoichiometric coefficients
k is rate constant
r is rate
Before calculating rate constant, first we have to determine reaction order.
In this question, the reactio order is 2. So, the rate law for it is
and the integrated formula is
in which
[A]₀ is initial concentration of reactant
Then, using initial concentration at initial time and final concentration at final time:
k = 0.422
The rate constant for the reaction is 0.422 M⁻¹.s⁻¹