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xz_007 [3.2K]
2 years ago
11

4.00L of a gas at 293K is compressed to fit a 1.5L bottle. What is the new temperature of the gas?

Chemistry
1 answer:
Anna007 [38]2 years ago
5 0

The new volume  temperature is  = 109.9 K

 <u><em> calculation</em></u>

The new volume temperature  is calculated  using Charles law  equation

That is V₁/T₁ =V₂/T₂

where;

V₁ = 4.00 L

T₁ = 293 k

V₂ = 1.5 L

T₂ = ?

make  T₂ the subject of the formula

T₂= V₂T₁/V₁

T₂  = {(1.5 L×  293 k) / 4.00 L} =109.9 K


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I need help question 7
algol [13]

Answer:

B

Explanation:

As you can see in these 4 examples, B- looks completely different from A, C, D! In B: The reactants and products are completely different in the Element Figures.

8 0
3 years ago
A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 degrees celsius,
Airida [17]

Answer:

0.714 liter.

Explanation:

Given:

The balloon initially has a volume of 0.4 liters and a temperature of 20 degrees Celsius.

It is heated to a temperature of 250 degrees Celsius.

Question asked:

What will be the volume of the balloon after he heats it to a temperature of 250 degrees Celsius ?

Solution:

By using:

PV=nRT

Assuming pressure as constant,

V∝ T

Now, let  K is the constant.

V = KT

Let initial volume of balloon , V_{1} = 0.4 liter

1000 liter = 1 meter cube

1 liter = \frac{1}{1000} m^{3} = 10^{-3} m^{3

0.4 liter = 0.4\times10^{-3}=4\times10^{-4} m^{3}

And initial temperature of balloon, T_{1} = 20°C = (273 + 20)K

                                                                          = 293 K

Let the final volume of balloon is V_{2}

And a given, final temperature of balloon, T_{2} is 250°C = (273 + 250)K

                                                                                          = 523 K

Now, V_{1} = KT_{1}

          4\times10^{-4}=K\times293\ (equation\ 1 )

V_{2} = KT_{2}

    =K\times523\ (equation 2)

Dividing equation 1 and 2,

 \frac{4\times10^{-4}}{V_{2} } =\frac{K\times293}{K\times523}

K cancelled by K.

By cross multiplication:

293V_{2} =4\times10^{-4} \times523\\V_{2} =\frac{ 4\times10^{-4} \times523\\}{293} \\          = \frac{2092\times10^{-4}}{293} \\          =7.14\times10^{-4}m^{3}

Now convert it into liter with the help of calculation done above.

7.14\times10^{-4} \times1000\\7.14\times10^{-4} \times10^{3} \\0.714\ liter

Therefore, the volume of the balloon be after he heats it to a temperature of 250 degrees Celsius is 0.714 liter.

5 0
2 years ago
Mg(OH)2 + HCl --&gt; MgCl2 + H2O
Rashid [163]
I am guessing you want us to balance this equation so.
To balance, we add another molecule of HCl to the left side of the equation and another molecule of water (H20) to the right side of the equation to give: 

<span>Mg(OH)2 + 2HCl = MgCl2 + 2H20 </span>
6 0
3 years ago
Can someone please explain this to me? I need help ​
Vladimir [108]

Answer:

The order would be: X-Rays, Visible Light, and Infrared Waves.

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Here is a list of all the types of waves in order from shortest wavelength to longest wavelengths:

Gamma Rays (Shortest Wavelengths, High Energy), then X-Rays would be the second strongest, then Ultraviolet waves, then Visible Light, then Infrared waves, then Microwaves, and lastly Radio Waves (Longest Wavelengths, Low Energy).

6 0
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