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hjlf
3 years ago
10

Which atoms have the highest electronegativity?

Physics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

Note that there is little variation among the transition metals. Electronegativities generally decrease from top to bottom within a group due to the larger atomic size. Of the main group elements, fluorine has the highest electronegativity (EN = 4.0) and cesium the lowest (EN = 0.79).

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A fast teaub abd a ski train driving from city a and city b face to face the fast train has a speed of 76km/h, the slow train ha
LekaFEV [45]

The distance between the two cities is 513.24 km.

<h3>Time of motion when the two trains meet</h3>

The time spent on the journey when the two trains meet is calculated as follows;

(Va - Vb)t = d

where;

  • d is the distance between the trains before meeting

(76 - 65)t = 40

11t = 40

t = 40/11

t = 3.64 hr

<h3>Distance traveled by the fast train</h3>

d1 = 76 km/h x 3.64 h

d1 = 276.64 km

<h3>Distance traveled by the slow train</h3>

d2 = 65 km/h x 3.64 h

d2 = 236.6 km

The distance between the two cities = 276.64 km + 236.6 km

                                                             = 513.24 km

Learn more about relative velocity here: brainly.com/question/17228388

7 0
2 years ago
In the image, not to scale, which phase of the moon would you observe from earth?​
timofeeve [1]

Answer:

The "new" moon phase is being shown because the moon shown is directly between the sun and earth and is not visible from the earth because of the brightess of the sun.

8 0
3 years ago
Which movement causes day and night on Earth?
Brilliant_brown [7]

Answer:

The rotation of Earth

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A train is speeding down a railroad track at the speed of 50 miles per hour. From whose reference point is the train not moving?
marysya [2.9K]

A: a person sitting on a train

Hence person could have a meal and not get food all over them.

3 0
4 years ago
A 1,550 kg car moving south at 10.0 m/s collides with a 2,550 kg car moving north. The cars stick together and move as a unit af
nikitadnepr [17]

Answer:

14.47 m/s

Explanation:

The momentum must be preserved before and after the collision:

The total momentum before the collision

m_1v_1 + m_2v_2

where m_1 = 1550 kg, m_2 = 2550 kg are the masses of the car moving south and north, respectively, before the collision. v_1 = -10m/s is the velocity of the car moving South. We take the velocity to the North as the positive direction

The total momentum after the collision

(m_1 + m_2)V

where V = 5.22m/s is the velocity of both cars after the collision

We can equalize the 2 equations and plug in the numbers:

m_1v_1 + m_2v_2 = (m_1 + m_2)V

1550(-10) + 2550*v_2 = (1550 + 2550)5.22

-15500 + 2550v_2 = 21402

2550v_2 = 36902

v_2 = 36902/2550 = 14.47 m/s

6 0
3 years ago
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