Answer:
counterclockwise and inward
Explanation:
Extratropical cyclones or mid-latitude cyclones are the low-pressure areas, along with anticyclones of the high-pressure areas that drive weather over much of the Earth.
<u>Due to the Coriolis effect, the flow of the wind around the extratropical cyclone is counterclockwise in direction in the northern hemisphere, and clockwise in direction in the southern hemisphere.</u>
<u>It forms a comma shape which drives the forces inward the center.</u>
Einstein's theory determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels.
Magnitude: Magnitude generally refers to the quantity or distance.
Attraction: A force that makes things move together and stay together.
Repulsive: The feeling of being repelled, as by the thought or presence of something; distaste, repugnance, or aversion.
Current: Current is the rate of flow of electric charge. A potential difference (voltage) across an electrical component is needed to make a current flow through it.
I hope that helps :]
Answer:
271.862 N/m
Explanation:
From Hook's Law,
mgh = 1/2ke²............... Equation 1
Where
m = mass of the ball, g = acceleration due to gravity, k = spring constant, e = extension, h = height fro which the ball was dropped.
Making k the subject of the equation,
k =2mgh/k²....................... Equation 2
Note: The potential energy of the ball is equal to the elastic potential energy of the spring.
Given: m = 60.3 g = 0.0603 kg, g = 9.8 m/s², e = 4.68317 cm = 0.0468317 m, h = 53.7 cm = 0.537 m
Substitute into equation 2
k = 2(0.0603)(9.8)(0.537)/0.048317²
k = 0.6346696/0.0023345
k = 271.862 N/m
The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.
The given parameters;
- time of fall of the first ball, t = 1 s
- time of fall of the second ball, t = 3 s
The distance traveled by each ball is calculated using the second equation of motion as shown below.
The distance traveled by the first ball is calculated as follows;

The distance traveled by the second ball is calculated as follows;

Thus, the second ball traveled a greater distance because it spent more time in motion.
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