Answer:
a)
b)
c)Xmax=80.71m
Explanation:
<u>a)Kinematics equation for the Stone, dropped:</u>


initial position is bridge height
the stone is dropped
The ball reaches the ground, y=0, at t=t1:


<u>b)Kinematics equation for the Stone, with a initial speed of 20m/s:</u>


initial position is bridge height
the stone is thrown straight down
The ball reaches the ground, y=0, at t=t1:


t2=-6.01 this solution does not have physical sense
t2=2.00
<u>c)Kinematics equation for the Stone, with a initial speed of 20m/s with an angle of 30° above the horizontal:</u>


initial position is bridge height
the stone is thrown with an angle of 30° above the horizontal
The ball reaches the ground, y=0, at t=t3:


t3=-2.62 this solution does not have physical sense
t3=4.66
the movement in x:
v=constant=20cos(30)m/s
x(t)=v*t
Xmax=v*t3=20cos(30)*4.66=80.71m