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juin [17]
3 years ago
10

Calculate the maximum capillary rise/fall of mercury in a 0.5 mm radius glass capillary. Assume that the surface tension for mer

cury is 0.51 Nm/s; Temperature is 15.5 C; specific gravity =13.3, and an angle made by mercury with the glass was measured to be 50o. Assume mercury and glass form a nonwetted surface (5 points).
Physics
1 answer:
tekilochka [14]3 years ago
8 0

Answer: 0.01 m

Explanation: The formulae for capillarity rise or fall is given below as

h = (2T×cosθ)/rpg

Where θ = angle mercury made with glass = 50°

T = surface tension = 0.51 N/m

g = acceleration due gravity = 9.8 m/s²

r = radius of tube = 0.5mm = 0.0005m

p = density of mercury.

h = height of rise or fall

From the question, specific gravity of density = 13.3

Where specific gravity = density of mercury/ density of water, where density of water = 1000 kg/m³

Hence density of mercury = 13.3×1000 = 13,300 kg/m³.

By substituting parameters, we have that

h = 2×0.51×cos 50/0.0005×9.8×13,300

h = 0.6556/65.17

h = 0.01 m

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Part a)

At t = 0  the position of the object is given as

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At t = 2

x = 2 sin(\pi/2) = 2cm

so displacement of the object is given as

d = 2 - 0 = 2cm

so average speed is given as

v_{avg} = \frac{2}{2} = 1 cm/s

Part b)

instantaneous speed is given by

v = \frac{dy}{dt}

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now at t= 0

v = \frac{\pi}{2} cm/s

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Part c)

Average acceleration is given as

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a_{avg} = \frac{0 - \frac{\pi}{2}}{2}

a = -\frac{\pi}{4} cm/s^2

Part d)

Now for instantaneous acceleration

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a = -\frac{\pi^2}{16} * 0 = 0 cm/s^2

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a = -\frac{\pi^2}{8}

<em>so above is the instantaneous accelerations</em>

7 0
3 years ago
Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer dista
nadezda [96]

Distance = (speed) x (time)

Car A: Distance = (8 m/s) x (43 s)  =  344 meters

Car B: Distance = (7 m/s) x (50 s)  =  350 meters

350 meters is a longer distance than 344 meters.

<em>Car-B traveled a longer distance</em> than Car-A did.

5 0
2 years ago
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Romeo (81.0 kg) entertains Juliet (53.0 kg) by playing his guitar from the rear of their boat at rest in still water, 2.70 m awa
den301095 [7]

Answer:

0.64 m

Explanation:

The first thing is calculate the center of mass of the system.

X_{cm}= \sum_{n=1}^{n}\frac{X_n\times M_n}{M_n}

now multiplying every coordinate x by the mass of each object (romeo, juliet and the boat) and dividing all by the total mass  taking by reference the position of juliet.

X_{cm}=\frac{53\times0 +81\times2.7+79\times1.35}{53+81+79}

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When the forces involved are internals, the center of mass don't change  

After the movement the center of mass remains in the same distance from the shore, but change relative to the rear of the boat.

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3 years ago
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PolarNik [594]

Answer:

The coin is denser than any of the liquids, and will sink through everything. The oil is the least dense liquid, so it will float on the water, and the syrup is the densest liquid, so it will sink below the water.

Explanation:

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larisa [96]

Answer:

Exchange Reaction

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The given reaction  AB + CD = AD + CB is known as exchange reaction

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Therefore, The type of example represented by the reaction  

AB + CD = AD + CB

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3 0
3 years ago
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